1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mr_godi [17]
4 years ago
14

Tell in short what is speed​

Physics
2 answers:
Alex17521 [72]4 years ago
6 0
<h3>✽ - - - - - - - - - - - - - - -  ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Speed is simply the rate of movement

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

sineoko [7]4 years ago
4 0

It is the distance travelled by an object in unit time

You might be interested in
A net force of 10.0 N causes an object to accelerate at 2.00m/s^2. What is the mass of the object?
madam [21]

5.00kg

random = abcdefghijklmnopqrstuvwxyz


4 0
4 years ago
A 560-g squirrel with a surface area of 930cm2 falls from a 5.0-m tree to the ground. Estimate its terminal velocity. (Use a dra
bija089 [108]

Explanation:

Terminal velocity is given by:

v_t=\sqrt{\frac{2mg}{\rho C_dA}}

Here, m is the mass of the falling object, g is the gravitational acceleration,  C_d is the drag coefficient, \rho is the fluid density through which the object is falling, and A is the projected area of the object. in this case the projected area is given by:

A=\frac{A_s}{2}=\frac{930cm^2}{2}=465cm^2\\465cm^2*\frac{1m^2}{10^4cm^2}=0.0465m^2\\560g*\frac{1kg}{10^3g}=0.56kg

Recall that drag coefficient for a horizontal skydiver is equal to 1 and air density is 1.28\frac{kg}{m^3}.

v_t=\sqrt{\frac{2(0.56kg)(9.8\frac{m}{s^2})}{(1.28\frac{kg}{m^3}(1)(0.0465m^2)}}\\v_t=13.58\frac{m}{s}

Without drag contribution the motion of the person is an uniformly accelerated motion, thus:

v_f^2=v_o^2+2gh\\v_f=\sqrt{2gh}\\v_f=\sqrt{2(9.8\frac{m}{s^2})(5m)}\\v_f=9.9\frac{m}{s}

7 0
3 years ago
An automobile rounds a curve of radius 50.0 m on a flat road.
bixtya [17]

Answer:

14m/s

Explanation:

Given parameters:

Radius of the curve  = 50m

Centripetal acceleration  = 3.92m/s²

Unknown:

Speed needed to keep the car on the curve = ?

Solution:

The centripetal acceleration is the inwardly directly acceleration needed to keep a body along a curved path.

 It is given as;

      a = \frac{v^{2} }{r}  

a is the centripetal acceleration

v is the speed

r is the radius

  Now insert the parameters and find v;

         v²   = ar

        v² = 3.92 x 50  = 196

         v  = √196 = 14m/s

6 0
3 years ago
The following is current scientific evidence supporting the nebular theory on the formation of the solar system. the composition
andreyandreev [35.5K]
All planets orbit the sun in a plane, all the planets orbit the sun in the same direction, most of the planets rotate in the same direction. I'm not sure when and answer ends or begins on your question so you can choose from some of the answers I gave you.
6 0
3 years ago
Read 2 more answers
A 93 kg zebra is traveling 13 m/s east. What is the zebra’s momentum?
Harlamova29_29 [7]
Equation: Mass x Velocity = Momentum

Answer: 93 x 13 = 1,209
3 0
3 years ago
Other questions:
  • An object weighs 7.84 N when it is in air and 6.86 N when it is immersed in water of density 1000 kg/m3. What is the density of
    12·1 answer
  • Professor Frank Nabarro insists that all senior physics majors take his notorious physics aptitude test. The test is so tough th
    5·1 answer
  • Use the graph to determine the object’s average velocity.
    9·1 answer
  • " when striking, the pike, a predatory fish, can accelerate from rest to a speed of 4.0 m/s in 0.11 s."
    5·1 answer
  • An Object moving 10 m/s undergoes acceleration for 6 seconds. If it moves 8 m to the left, find the acceleration
    12·1 answer
  • Describe a real-world example of the law of conservation of momentum.
    8·1 answer
  • In which direction does gravitational force act
    13·1 answer
  • HELP ITS DUE IN 4 MINUTES
    9·1 answer
  • 3+3+##+=484hcfngccnfjkr,hca,nkvn,zhjcf v
    7·1 answer
  • A 600kg lifts starts from rest. It moves upward for 3.00 s with a constant acceleration until it reaches its final speed of 1.55
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!