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jeka57 [31]
3 years ago
9

If 5+20*2^(2-3x)=10*2^(-2x)+5, what is the value of x? a –3 b –2 c 2 d 3

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
6 0
Step 1: get rid of the +5 on both sides.
Step 2: divide by 10 on both sides

Then you have: 2*2^(2-3x) = 2^(-2x)

The factor 2 on the left can be brought into the exponent because you're simply multiplying with 2 more...

2^(1+2-3x) = 2^(-2x)

Now you can equate the exponents:

3-3x = -2x => 3 = -2x+3x => x=3

so d is your answer.
RUDIKE [14]3 years ago
3 0

Answer: 3

ya welcome

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Answer:

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Step-by-step explanation:

we know that

A linear equation in slope intercept form is equal to

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or say b is the actual weight of the wrestler.

In this problem

m=5.5 kg/month

Let

W ⇒ the sumo wrestler's weight in kg (dependent variable)

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The linear equation is equal to

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substitute in the linear equation to find the value of b

140 = 5.5\times11 +b\\140 = 60.5+b\\b = 140-60.5\\b = 79.5\ kg

W(t)= 5.5t+79.5

Hence,The equation for the relationship between the weight and number of months is W(t)= 5.5t+79.5

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