2 × 7/8 as a model how do I draw it as a model

1 answer:

7 0

One way to do it is you can draw two sets of 7/8.

You can draw 8 tiles, and color in 7.

Draw that two times.

That’s one way, but that might not be the way you learned it.

Hope this helped anyways!

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Clare spent a total of 25 minutes at the track. She spent 5 minutes stretching and walked 4 laps around the track. If she walked

andrezito [222]

Hello!

First of all, we can subtract the stretching time. This gives us 20. If we divide by the four laps we get 5 minutes per lap.

Now, one lap is 400 meters (most tracks are), which is equal to 15,748.03 inches. This means it takes her five minutes to walk 15,748.03 inches. This is also equal to 300 seconds, so it takes her 300 minutes per 15,748.03 inches.

But if we round our big inches number to the nearest ten thousandth, we get 16,000, so in a simpler form her pace is 300/16,000. But we need to find in per second. Therefore we will divide by 300 to find how many inches she walks per second. This means she walks about 53.33 inches per second.

I hope this helps!

6 0

3 years ago

Read 2 more answers

If 4 dice are rolled, what is the number of ways in which at least 1 die shows 3?

UkoKoshka [18]

I think the number of ways is 671?

4 0

3 years ago

A metal hollow bar whose cross section and dimension are shown below weighs 8x10^3 kg/m^3 and measure 2m in length ..determine t

devlian [24]

1) We calculate the volume of a metal bar (without the hole).

volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²

Volume=(0.935 m²)(2 m)=1.871 m³

2) we calculate the volume of the parallelepiped

Volume of a parallelepiped= area of the section x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³

3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar - volume of a parallelepiped

Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³

4) we calculate the mass of the metal bar

density=mass/ volume ⇒ mass=density *volume

Data:
density=8.10³ kg/m³
volume=1.551 m³

mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg

answer: The mas of the metal bar is 12.408x10³ kg or 12408 kg

4 0

3 years ago

Quadrilateral ABCD is rotated 270° clockwise about the origin. What are the

mote1985 [20]

Answer:

C. I took the quiz

Step-by-step explanation: