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Ne4ueva [31]
3 years ago
13

2 × 7/8 as a model how do I draw it as a model

Mathematics
1 answer:
White raven [17]3 years ago
7 0
One way to do it is you can draw two sets of 7/8.


You can draw 8 tiles, and color in 7.

Draw that two times.

That’s one way, but that might not be the way you learned it.


Hope this helped anyways!
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How many 2/3 ounce portions of chocolate can Anna get from the 42/3 ounces of chocolate she bought at Union Market?
Lelechka [254]
She can get 21 portions. Since 2/3 and 42/3 already share the same denominator, all you need to do is divide 42 by 2 to get 21.
6 0
3 years ago
Find the next two numbers in the pattern<br><br> 12500, -2500, 500, -100,...
astraxan [27]
The pattern first of all is divide the number by -5. (12500/ -5 = -2500, and so on) Since we know that, you divide -100 by -5 which gets you 20, then 20 by -5 which gets you -4.

The next two numbers are 20, and -4

Hope this helps!
7 0
3 years ago
What is 12 and 19 /20 as a decimal?
-BARSIC- [3]

12.95

Hope this helps! ;)

6 0
3 years ago
Read 2 more answers
A system of two linear inequalities is graphed as shown, where the solution region is shaded.
Zinaida [17]

Answer:

(-3,2) is located in the solution region.

Step-by-step explanation:

3 0
3 years ago
Simplify without the absolute value |x+3| ; if x&gt;2
inna [77]

Answer:

x+3 if x>2

Step-by-step explanation:

Recall some following basic ideas about absolute value:

|0|=0 or I guess -(0)=0

|3|=3

|-3|=-(-3) or just 3 but there is a reason why I wrote it the way I did.

You see that the absolute value returned the same value if the value was positive.

You see that the absolute value returned the opposite value if the value was negative.

You can include 0 in either.

Let's look at |x+3| alone for a second.

*|x+3|=x+3 if x+3 is positive or zero.

When is x+3 positive or zero? [greater than or equal to 0]

x+3\ge 0

Subtract 3 on both sides

x\ge -3

*|x+3|=-(x+3) if x+3 is negative or zero.

When is x+3 negative or zero? [less or equal to 0]

x+3\le 0

Subtract 3 on both sides

x\le -3

So looking at the bullet points (the *), x>2 fits into the first inequality.

Therefore, |x+3|=x+3.

8 0
3 years ago
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