Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
Answer:
True.
Step-by-step explanation:
If I = prt, They are all being multiplied together, therefor being constant.
100000+200000=300000
28x=300000
X=10714
They would need to make $10714 a night
Answer:
4 Is greater than 10. Hope this helped.
This is the concept of areas of solid figures. The surface are of the solid figure formed when 2 square pyramids are attached will be given by:
SA=[number of triangular faces]*[Area of each triangle]
Number of triangular faces=8
Area of each triangle=1/2*bh
base=6/4=1.5 cm
height=2 cm
thus;
Area=1/2*2*1.5=1.5
The surface area will therefore be:
SA=1.5*8=12cm^2
