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Aleonysh [2.5K]
3 years ago
7

The diameter of a Frisbee is 12 in. What is the area of the Frisbee?

Mathematics
1 answer:
boyakko [2]3 years ago
4 0
The area of the Frisbee is 36π square inches or approximately 113.04 square inches.

Since the Frisbee is circular, its area can be solved by the equation:
A = πr^2 where r= diameter/2 = 6 in
A = 6*6π in
A = 36π square inches or approximately <span>113.04 square inches

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Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.

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Option A is correct.

Step-by-step explanation:

We need to find the solution of:

\sqrt{x^2+49}=x+5

Solving:

Taking square on both sides:

(\sqrt{x^2+49})^2=(x+5)^2\\x^2+49=x^2+2(x)(5)+25\\Simplifying:\\x^2+49-x^2-10x-25=0\\-10x+24=0\\-10x=-24\\x=\frac{-24}{-10}\\ x=\frac{24}{10}\\x=\frac{12}{5}

Verifying the solution by putting x = 12/5 in the given equation, we get true result.

So, x=\frac{12}{5} or x= twelve-fifths

Option A is correct.

Keywords: Solving Square root Equations

Learn more about Solving Square root Equations at:

  • brainly.com/question/4034547
  • brainly.com/question/1716201
  • brainly.com/question/10666510

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