Answer:
Step-by-step explanation:
Given y = coskt
y' = -ksinkt
y'' = -k²coskt
Substitute this y'' into the expression 25y'' = −16y
25(-k²coskt) = -16(coskt)
25k²coskt = 16(coskt)
25k² = 16
k² = 16/25
k = ±√16/25
k = ±4/5
b) from the DE 25y'' = −16y
Rearrange
25y''+16y = 0
Expressing using auxiliary equation
25m² + 16 = 0
25m² = -16
m² = -16/25
m = ±4/5 I
m = 0+4/5 I
Since the auxiliary root is complex number
The solution to the DE will be expressed as;
y = Asinmt + Bsinmt
Since k = m
y = Asinkt+Bsinkt where A and B are constants
Answer:
927.0 cm²
Step-by-step explanation:
Step 1: find Z
m < Z = 180 - (28 + 118) (sum of ∆)
= 180 - 146
Z = 34°
Step 2: Find side XY using the law of sines
Cross multiply
Divide both sides by 0.469
XY ≈ 50 cm
Step 3: find the area.
Area of ∆ = ½*XY*YZ*sin(Y)
XY ≈ 50 cm
= ½*50*42*sin(118)
= 25*42*0.8829
Area = 927.045
Area ≈ 927.0 cm² (nearest tenth)
Answer:
I think f(t)=1/4t
Step-by-step explanation:
Because of you multiply 1/8 times 2, it gives you 1/4. Not 100% sure tho
Answer:
20
Step-by-step explanation:
Calculate 10% of total = 3 / 1.5 = 2
Multiply by 10x since 10% is 1/10 of 100%
2 x 10 = 20
Answer: First Option : Sₙ= n/2(a₁ + aₙ)
Step-by-step explanation:
The nth partial sum of an arithmetic sequence or the sum of the first n terms of the arithmetic series can be defined as the sum of a finite number of term in an arithmetic sequence.
It is calculated using the formula:
Sₙ= n/2(a₁ + aₙ)
Where :
a₁ = First term
aₙ = last term
n = number of terms
