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Aleonysh [2.5K]
3 years ago
7

The diameter of a Frisbee is 12 in. What is the area of the Frisbee?

Mathematics
1 answer:
boyakko [2]3 years ago
4 0
The area of the Frisbee is 36π square inches or approximately 113.04 square inches.

Since the Frisbee is circular, its area can be solved by the equation:
A = πr^2 where r= diameter/2 = 6 in
A = 6*6π in
A = 36π square inches or approximately <span>113.04 square inches

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Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.

<span> </span>

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Will give 60 points if completed. Please help me!
Lerok [7]

Convert all the numbers to real numbers:

6√3 = 10.3923

(3.5)^2 = 12.25

√75 = 8.660

9.8 = 9.8

57/5 = 11.4

A)  Now order from largest to smallest:

(3.5)^2, 57/5, 6√3, 9.8, √75

B) We found the order by solving the equations to get real numbers.

C)

Since the numbers are multiplied by a negative number, the greatest number would be the smallest number because it would be closer to zero.

The order would be the reverse of part A:

x√75, 9.8x,  6x√3, 57x/5, x(3.5)^2

D) I replaced x with -1 and calculated for real numbers. All the values were the same as A except they were the negative value.

8 0
4 years ago
Read 2 more answers
Determine the intercepts of the line 4x-3y=17
bezimeni [28]

Answer:

x-intercept = 17/4 and y = -17/3

Step-by-step explanation:

To find the intercepts: set x = 0 for the y-intercept and solve the equation and set y =0 for the x- intercept and solve the equation.

To

4x - 3y = 17

4(0) - 3y = 17

0 - 3y = 17

  y = 17 /-3

 y = -17/3 = -5 2/3       y-intercept = -5 2/3.

The ordered pair on the graph is (0, -17/3)

   4x - 3(0) = 17

     4x - 0 = 17

      4x = 17

       x = 17/4       x-intercept = 17/4

    The ordered pair on the graph is (17/4, 0)

3 0
3 years ago
X^2+4x+20=12x-5<br><br> Solve this equation
Scrat [10]

Answer:

4 + (or -) 3i

Step-by-step explanation:

Hi!

Alright, so we're going to move all of the variables and constants to one side. Then, using the quadratic formula, we'll find the answer.

1. Move 12x-5 to the left side of the equation by

  a. Subtracting 12x from both sides

  b. adding 5 to both sides.

1: x^2+4x+20-12x+5

2. Group the common terms

  x^2+4x-12x+20+5 --> x^2-8x+25

3. Look at the problem. We can't factor this.

Explanation for why this isn't factorable (you can skip this)

(1) 25 is positive, so its two factors will both be either positive or negative. We're looking for a negative 8, so let's go with negative.

(2) Factors of 25: 1 & 25, 5 &5

Seeing the problem? Ya, none of the factors of 25 sum to eight. So, instead, we're going to use the quadratic formula.

4.  So, the quadratic formula: \frac{-b+-\sqrt{b^2-4ac} }{2a}

Our equation is x^2-8x+25=0

a is the constant in front of the x^2

b is the constant in front of the x

c is the term without any x values

so, a=1, b=-8, and c= 25

Into equation:

\frac{8+-\sqrt{64-4(1)(25)} }{2a}=\frac{8+-\sqrt{64-100} }{2}=\frac{8+-\sqrt{-36} }{2}

8/2 = 4

sqrt(-36) = 6i

6i/2 = 3i (remember, we still have the two in the denominator)

4 + (or -) 3i

8 0
3 years ago
Read 2 more answers
I need help only 10 points today
gtnhenbr [62]

Answer:

D is the correct answer

Step-by-step explanation:

hopes this helps

6 0
3 years ago
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What is the slope of the line that passes through the points (2,0) and
Y_Kistochka [10]

Answer:

slope = - \frac{1}{6}

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (2, 0) and (x₂, y₂ ) = (32, - 5)

m = \frac{-5-0}{32-2} = \frac{-5}{30} = - \frac{1}{6}

3 0
3 years ago
Read 2 more answers
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