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Aleonysh [2.5K]
3 years ago
7

The diameter of a Frisbee is 12 in. What is the area of the Frisbee?

Mathematics
1 answer:
boyakko [2]3 years ago
4 0
The area of the Frisbee is 36π square inches or approximately 113.04 square inches.

Since the Frisbee is circular, its area can be solved by the equation:
A = πr^2 where r= diameter/2 = 6 in
A = 6*6π in
A = 36π square inches or approximately <span>113.04 square inches

</span>

Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.

<span> </span>

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The point A(–1, 4) is translated five units right and three units down. Which rule describes the translation?
lozanna [386]

Answer: SECOND OPTION.

Step-by-step explanation:

Given the following point identified as "A":

A(-1,4)

You can identify that the x-coordinate of the point is:

x=-1

And its y-coordinate is:

y=4

According to the exercise, this point is translated five units right and three units down. This means that, in order to find the new coordinates, you need to add 5 to the original x-coordinate and subtract 3 from the original y-coordinate.

Therefore, you can conclude that the rule that best describe the translation of the point A(-1,4) is the following:

(x,y) → (x+5,y-3)

Then, the point translated is:

A'(-1+5,\ 4-3) → A'(4,1)

6 0
3 years ago
Read 2 more answers
Phoebe compared the cost of books in 9 different stores.
krek1111 [17]
You have to put the numbers in order and find the middle value so in this case it's-

2, 4, 4, 5, 6, 7, 8, 8, 8 

The answer is $6
7 0
3 years ago
Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b
poizon [28]

The roots of the given polynomials exist  $x=8+\sqrt{10}$, and $x=8-\sqrt{10}$.

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\

$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\

$&x=8+\sqrt{10}, x=8-\sqrt{10}

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$, and

$x=8-\sqrt{10}$.

To learn more about quadratic equations refer to:

brainly.com/question/1214333

#SPJ4

3 0
1 year ago
Read 2 more answers
1.
ASHA 777 [7]

Answer:

Step-by-step explanation:

Vertex A of the triangle ABC when rotated by 90° counterclockwise about the origin,

Rule to be followed,

A(x, y) → P(-y, x)

Therefore, A(1, 1) → P(-1, 1)

Similarly, B(3, 2) → Q(-2, 3)

C(2, 5) → R(-5, 2)

Triangle given in second quadrant will be the triangle PQR.

If the point P of triangle PQR is reflected across a line y = x,

Rule to be followed,

P(x, y) → X(y, x)

P(-1, 1) → X(1, -1)

Similarly, Q(-2, 3) → Y(3, -2)

R(-5, 2) → Z(2, -5)

Therefore, triangle given in fourth quadrant is triangle XYZ.

6 0
3 years ago
Which of the following terms correctly describe the object below?
Ratling [72]
The correct answers are A, D, E
5 0
3 years ago
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