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Ksenya-84 [330]
3 years ago
15

An 8-sided die is formed when two square pyramids are attached by their bases. The perimeter of the base shape is 6 centimeters.

The distance between the tallest points of the two pyramids is 2 centimeters. What is the surface area of the 8-sided figure?
Mathematics
1 answer:
Vlada [557]3 years ago
3 0
This is the concept of areas of solid figures. The surface are of the solid figure formed when 2 square pyramids are attached will be given by:
SA=[number of triangular faces]*[Area of each triangle]
Number of triangular faces=8
Area of each triangle=1/2*bh
base=6/4=1.5 cm
height=2 cm
thus;
Area=1/2*2*1.5=1.5
The surface area will therefore be:
SA=1.5*8=12cm^2
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Step-by-step explanation:

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In the given equations, after comparing with the general form

a_1 = 4\\b_1 = 5 \\c_1 = 10\\a_2 = A\\b_2 =B\\c_2 = 16

"In order for a system of equations to have infinity many solutions,

\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} "

Putting the values we get

\frac{4}{A} = \frac{5}{B} = \frac{10}{16}\\\frac{4}{A} = \frac{5}{B} = \frac{5}{8}\\Now\\\frac{4}{A} = \frac{5}{8}\\\frac{A}{4} = \frac{8}{5}\\A = \frac{8}{5} * 4\\A = \frac{32}{5}\\And\\\frac{5}{B} = \frac{5}{8}\\\frac{B}{5} = \frac{8}{5}\\B = 8

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