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2 years ago

Round 67,436,828,104 to the nearest million

1 answer:

3 0

67,436,828,104 rounded to the nearest million is 67,437,000,000. To round to the nearest million, you first check to see what is in the hundred-thousands place. If the number in the hundred-thousands place is a number between 0-4, the millions place stays the same. If the number in the hundred-thousands is 5-9, the millions place value goes up one.

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Which quotient matches the description of solving with partial quotients for 240÷15

Illusion [34]

Answer:

C. 16

Step-by-step explanation:

240/15

Step one: 10x15= 150

240-150= 90

Partial quotient: 10

Step two: 6x15= 90

90-90= 0

Partial quotient: 6

Step 3: 10+6= 16

Answer check: 240/15= 16

3 0

2 years ago

Anyone know how to do this?

IrinaVladis [17]

H(x) = x - 5

However, it had a domain of all real numbers such that x does not equal 3, since that would cause you to divide by 0.

7 0

2 years ago

Read 2 more answers

According to government data, 20% of employed women have never been married. If 10 employed women are selected at random, what i

Ierofanga [76]

Answer:

a) $P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

b) $P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)$

$P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107$

$P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268$

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

And replacing we got:

$P(X\leq 2) = 0.107+0.268+0.302=0.678$

c) For this case we want this probability:

$P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)$

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

$P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302$

$P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268$

$P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107$

And replacing we got:

$P(X \geq 8) = 0.677$

And replacing we got:

$P(X\geq 8)=0.0000779$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Bin (n=10 ,p=0.2)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Let X the random variable "number of women that have never been married" , on this case we now that the distribution of the random variable is:

$X \sim Binom(n=10, p=0.2)$

Part a

We want to find this probability:

$P(X=2)$

And using the probability mass function we got:

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

Part b

For this case we want this probability:

$P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)$

We can find the individual probabilities and we got:

$P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107$

$P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268$

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

And replacing we got:

$P(X\leq 2) = 0.107+0.268+0.302=0.678$

Part c

For this case we want this probability:

$P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)$

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

$P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302$

$P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268$

$P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107$

And replacing we got:

$P(X \geq 8) = 0.677$

3 0

2 years ago

For the sphere shown, r = 4.2 cm.<br> What is its volume, to the nearest cubic centimeter?

DochEvi [55]

V = 4/3(pi)(r^3)
V = 4/3(pi)(4.2^3)
V = 310 cm^3

Good luck!

8 0

2 years ago

over a two week period Julie had the following number of math homework problems given each day:20,0,7,10,11 0,25,15,1 find the m

kvv77 [185]

Mean: Add all the numbers and divide by the amount of numbers.

20 + 0 + 7 + 10 + 11 + 0 + 25 + 15 + 1 = 89
89/9 = 9.889 (rounded)

Mean = 9.889 (rounded)

Median: Reorder from least to greatest, and the middle number is the median.
0, 0, 1, 7, 10, 11, 15, 20, 25

The middle number is 7

Median = 7

Mode: The number that shows up the most.
Mode = 0, which shows up one time more than all the other numbers

Range: Subtract the greatest number with least number

25 - 0 = 25

Range = 25

hope this helps

3 0

2 years ago

Read 2 more answers