Point J' would be located at (5,0)
Answer:
The vertex of this parabola, 
, can be found by completing the square.
Step-by-step explanation:
The goal is to express this parabola in its vertex form:
,
where 
, 
, and 
are constants. Once these three constants were found, it can be concluded that the vertex of this parabola is at 
.
The vertex form can be expanded to obtain:
.
Compare that expression with the given equation of this parabola. The constant term, the coefficient for 
, and the coefficient for 
should all match accordingly. That is:
.
The first equation implies that is equal to 
. Hence, replace the "
" in the second equation with 
to eliminate 
:
.
.
Similarly, replace the "" and the "" in the third equation with and 
, respectively:
.
.
Therefore, 
would be equivalent to 
. The vertex of this parabola would thus be:
.
Answer:
x=-48
Step-by-step explanation:
Add 4 to both sides and then multiply both sides by 3.
Answer:
20.1246118 or 20.12
Step-by-step explanation:
First draw the box with the diagonal, as you can see it is split into 2 equal right triangles. Now use the pythagorean theorem (a^2+b^2=c^2) to find the length of the diagonal
