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Semenov [28]
4 years ago
15

The population of a local species of dragonfly can be found using an infinite geometric series where a1 = 30 and the common rati

o is two fifths. Write the sum in sigma notation and calculate the sum that will be the upper limit of this population.
Mathematics
1 answer:
Doss [256]4 years ago
6 0

Answer:

The answer is the summation of 30 times two fifth of the i minus 1 power from equation equals to 1, the sum is 50.

Explanation:

S = a ÷ (1-r)

S = 30 ÷ (1- (2÷5))

S = 50.

The sum is 50.

By sigma notation verifies 30.

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3 years ago
Write 5/10 in three equivalent forms
krek1111 [17]

equivalent fractions are fractions which have the same value.

equivalent fractions all have the same simplified form

we can write equivalent fractions by multiplying both numerator and denominator by the same number. We can also write equivalent fractions by dividing both numerator and denominator by the same number

so 5/10

we can get the equivalent fractions by multiplying by a common number

when we multiply by 2

\frac{5}{10}* 2= \frac{5*2}{10*2} = \frac{10}{20}

when we multiply by 3

\frac{5}{10}* 3 = \frac{5*3}{10*3} = \frac{15}{30}

when we multiply by 4

\frac{5}{10} *4 = \frac{5*4}{10*4}  = \frac{20}{40}

the three equivalent fractions are

10/20 , 15/30, 20/40

5 0
4 years ago
Read 2 more answers
A field researcher is gathering data on the trunk diameters of mature pine and spruce trees in a certain area. The following are
lidiya [134]

Answer:

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

Step-by-step explanation:

Using a .10 significance level, can he conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree

The null hypothesis is that they are equal(that is, subtraction between the means is 0), while the alternate hypothesis is that they are greater(that is, subtraction between the means is larger than 0). So

H_0: \mu_1 - \mu_2 = 0

H_a: \mu_1 - \mu_2 > 0

In which \mu_1 is the mean pine trees height while \mu_2 is the mean spruce trees height.

The test statistic is:

z = \frac{X - \mu}{s}

In which X is the sample mean, \mu is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that \mu = 0

Mean trunk diameter (cm) 35 30:

Pine trees - 35

Spruce trees - 30

The sample mean is given by the subtraction of the means. So

X = 35 - 30 = 5

Sample Size 40 80

Population variance 160 160

This means that the standard error for each sample is given by:

s_1 = \frac{\sqrt{160}}{\sqrt{40}} = 2

s_1 = \frac{\sqrt{160}}{\sqrt{80}} = \sqrt{2}

The standard error of the difference is the square root of the sum squared of the standard error of each sample.

s = \sqrt{2^2 + (\sqrt{2})^2} = \sqrt{6} = 2.4495

Test statistic:

z = \frac{X - \mu}{s}

z = \frac{5 - 0}{2.4495}

z = 2.04

Pvalue of the test:

Probability of a sample mean larger than 5, which is 1 subtracted by the pvalue of Z when X = 5.

Looking at the z-table, z = 2.04 has a pvalue of 0.9793.

1 - 0.9793 = 0.0207

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

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3 years ago
A rectangle is 5 inches long and 7 inches wide.How many one-square-inch tiles are needed to cover its area?
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Answer:

35 square inches

Step-by-step explanation:

The formula is bh

b being base and h being height. In this, the width is height and length is base.

5 times 7 is 35

Mark me as brainliest if this helps!

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