Answer:
R=-13
Step-by-step explanation:
S=-1-r/5-2
4=-1-r/3
Cross multiply
4*3=-1-r
12=-1-r
Collect like terms
12+1=-r
-r=13
Divide both sides by -
r=-13
It’s the third one, if not I’m sorry
SUM OF ANGLES IN A TRIANGLE THEOREM (SATT)
Radius, r = 3
The equation of a sphere entered at the origin in cartesian coordinates is
x^2 + y^2 + z^2 = r^2
That in spherical coordinates is:
x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)
where you can make u = r cos(phi) to obtain the parametrical equations
x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u
where theta goes from 0 to 2π and u goes from -r to r.
In our case r = 3, so the parametrical equations are:
Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
First what you need to do is find the HCF of both numbers.
After you've done that if it is 1 then they are what we call co-prime.
Now, if they are other than 1 they are not co-prime.
