<h3>
<u>Answer the following questions :-</u></h3>
Raja is junk seller. He sells many things. Here is given the list of junk.
Check the Raja's rate list and solve the following questions.

<h2>
<u>Solutions :-</u></h2>
1. How much money will you pay to Raju for 20 kg of newspapers?




<u>∴ We need to pay Rs.100 for buy 20 kg of newspapers. </u>

2. What is the cost of 5 kg Iron?




<u>∴ The cost of 5 kg iron is Rs.50.</u>

3. What is the cost of 9 kg Plastic?




<u>∴ The cost of 9 kg plastic is Rs.72. </u>

4. What is the cost of 7 kg Brass?



<u>∴ The cost of 7kg brass is Rs.350.</u>

Answer:
$2 was the dollar gain for the stock XYZ
V = s^2 +1/2sh
Reorder so common terms are on one side.
s^2 +(sh)/2 = v
Subtract s^2 from both sides.
(sh)/2 = -s^2 +v
Multiply both sides of the equation by 2.
sh = -s^2 *2 +v *2
Simplify each term.
sh = -2s^2 +2v
Divide each term by s and simplify.
h = -2s + (2v)/s
If <em>x</em> is the smallest of the three, then the next two integers are <em>x</em> + 2 and <em>x</em> + 4.
"Twice the largest is 20 less than the sum of all three" translates to
2 (<em>x</em> + 4) = (<em>x</em> + (<em>x</em> + 4) + (<em>x</em> + 6)) - 20
Solve for <em>x</em> :
2<em>x</em> + 8 = 3<em>x</em> - 10
<em>x</em> = 18
Then the three numbers are {18, 20, 22}.
1.60 *3 is 4.80-1.95=2. 85 a large container is $2.85