All categories

2 years ago

Element X is a radioactive isotope such that every 25 years, its mass decreases by

Mathematics

1 answer:

luda_lava [24]2 years ago

6 0

Answer: 26

Step-by-step explanation:

You might be interested in

Answer the following questions.

schepotkina [342]

<h3>Answer the following questions :-</h3>

Raja is junk seller. He sells many things. Here is given the list of junk.

Check the Raja's rate list and solve the following questions.

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \small\boxed{\begin{array}{c|c} \bf{Kind \: of\:junk} & \bf{Price \: of \: 1 \: kg } \\ \dfrac{\qquad\qquad\qquad}{ \sf News \: Paper} &\dfrac{\qquad \qquad\qquad}{ \sf Rs.5} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Iron} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.10} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Brass} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.50} & \\ \dfrac{\qquad\qquad\qquad}{ \sf Plastic} &\dfrac{\qquad\qquad\qquad}{ \sf Rs.8}&\end{array}} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

<h2>Solutions :-</h2>

1. How much money will you pay to Raju for 20 kg of newspapers?

$\quad{\longrightarrow{\sf{Cost \: of \: 1 \: kg \: newspaper = Rs.5}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 20 \: kg \: newspaper = Rs.20 \times 5}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 20 \: kg \: newspaper = Rs.100}}}$

$\quad{\longrightarrow{\underline{\boxed{\sf{\purple{Cost \: of \: 20 \: kg \: newspaper = Rs.100}}}}}}$

∴ We need to pay Rs.100 for buy 20 kg of newspapers. 

$\rule{200}{1.5}$

2. What is the cost of 5 kg Iron?

$\quad{\longrightarrow{\sf{Cost\: of \: 1 \: kg \: iron = Rs.10}}}$

$\quad{\longrightarrow{\sf{Cost\: of \: 5 \: kg \: iron = Rs.10 \times 5}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 5 \: kg \: iron = Rs.50}}}$

$\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost \: of \: 5 \: kg \: iron = Rs.50}}}}}$

∴ The cost of 5 kg iron is Rs.50.

$\rule{200}{1.5}$

3. What is the cost of 9 kg Plastic?

$\quad{\longrightarrow{\sf{Cost \: of \: 1 \: kg \: plastic = Rs.8}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 9 \: kg \: plastic = Rs.8 \times 9}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 9 \: kg \: plastic = Rs.72}}}$

$\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost\: of \: 9 \: kg \: plastic = Rs.72}}}}}$

∴ The cost of 9 kg plastic is Rs.72. 

$\rule{200}{1.5}$

4. What is the cost of 7 kg Brass?

$\quad{\longrightarrow{\sf{Cost \: of \: 1 \: kg \: brass = Rs.50}}}$

$\quad{\longrightarrow{\sf{Cost\: of \: 7 \: kg \: brass = Rs.50 \times 7}}}$

$\quad{\longrightarrow{\sf{Cost \: of \: 7 \: kg \: brass = Rs.350}}}$

$\quad{\longrightarrow\underline{\boxed{\sf{\purple{Cost \: of \: 5 \: kg \: brass = Rs.350}}}}}$

∴ The cost of 7kg brass is Rs.350.

$\underline{\rule{200pt}{2pt}}$

7 0

2 years ago

C. A share of stock XYZ went from $40 a to $42 & What was the dollar gain for the stock XYZ?

Afina-wow [57]

Answer:

$2 was the dollar gain for the stock XYZ

5 0

2 years ago

V=s^2+ 1/2sh, solve for H.

vladimir1956 [14]

V = s^2 +1/2sh
Reorder so common terms are on one side.
s^2 +(sh)/2 = v
Subtract s^2 from both sides.
(sh)/2 = -s^2 +v
Multiply both sides of the equation by 2.
sh = -s^2 *2 +v *2
Simplify each term.
sh = -2s^2 +2v
Divide each term by s and simplify.

h = -2s + (2v)/s

3 0

3 years ago

Find three consecutive even integers so that twice the largest

vekshin1

If x is the smallest of the three, then the next two integers are x + 2 and x + 4.

"Twice the largest is 20 less than the sum of all three" translates to

2 (x + 4) = (x + (x + 4) + (x + 6)) - 20

Solve for x :

2x + 8 = 3x - 10

x = 18

Then the three numbers are {18, 20, 22}.

7 0

2 years ago

Read 2 more answers

A large container of juice cost $1.95 less than three times the cost of the small container of juice what is the cost of a launc

deff fn [24]

1.60 *3 is 4.80-1.95=2. 85 a large container is $2.85

3 0

2 years ago