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Kaylis [27]
3 years ago
12

A storage pod was rented to hold merchandise for a sporting event. the boxes of merchandise are 1 cubic foot each. The volume of

the inside of the storage pod is 1280 cubic feet. What are some possible dimensions, in feet, of the storage pod being used?
Mathematics
2 answers:
Mumz [18]3 years ago
5 0

Since 1280=2^8\cdot 5, the dimensions (only integer) that gives the volume of the storage pod 1280 cubic feet are:

1 ft·1 ft· 1280 ft,

1 ft·2 ft· 640 ft,

1 ft·4 ft· 320 ft,

1 ft·8 ft· 160 ft,

1 ft·16 ft· 80 ft,

1 ft·32 ft· 40 ft,

1 ft·64 ft· 20 ft,

1 ft·128 ft· 10 ft,

1 ft·256 ft· 5 ft,

2 ft·2 ft· 320 ft,

2 ft·4 ft· 160 ft,

2 ft·8 ft· 80 ft,

2 ft·16 ft· 40 ft,

2 ft·32 ft· 20 ft,

2 ft·64 ft· 10 ft,

2 ft·128 ft· 5 ft,

4 ft·4 ft· 80 ft,

4 ft·8 ft· 40 ft,

4 ft·16 ft· 20 ft,

4 ft·32 ft· 10 ft,

4 ft·64 ft· 5 ft,

5 ft·8 ft ·32 ft,

5 ft·16 ft ·16 ft,

8 ft·8 ft ·20 ft,

8 ft·16 ft ·10 ft.

You can put the boxes of merchandise of volume 1 cubic foot each. If solve this question in integer numbers, then the dimensions of the box is 1 ft·1 ft· 1 ft and you can fit 1280 boxes in each storage pod listed above. If solve this question not only in integers, then there are a great amount of possible dimensions of a storage pod and boxes (for example, storage box has dimensions 0.5 ft· 2 ft· 1280 ft and boxes have dimensions 0.5 ft·2 ft· 1 ft and so on).

Bumek [7]3 years ago
3 0
There are a large number of possibilities, since each box is 1 cubic foot. We do not know the exact dimensions of each box (could be 1 ft x 1 ft x 1 ft, or 2 ft x 0.5 ft x 1 ft, or 4 ft x 0.5 ft x 0.5 ft). But in the simplest case, where each box is 1 ft x 1 ft x 1 ft, some possible dimensions are:
10 ft x 16 ft x 8 ft
20 ft x 8 ft x 8 ft
5 ft x 16 ft x 16 ft
10 ft x 32 ft x 4 ft
And so on, as long as each of the storage box dimensions are divisible by the dimensions of the boxes (in this case, 1 ft)
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Suppose we write the numbers $1,2,3,4,5,6$, and then color each number red or blue. The coloring is called factorific if there i
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The probability that his coloring is factorific is 0.28125

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For calculate the probability is necessary to identify the total number of ways to color the six number. This can be calculate with the rule of multiplication as:

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For know the number of ways in which the coloring is factorific, first we need to identify the divisors of each number:

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6: The divisors are 6, 3 and 1

From these information we analyse that for made a factorific coloring, is necessary that the number 1 is color blue. Additionally if the number 4 is color blue, the number 2 needs to be color blue and if the number 6 is blue, the number 3 needs to be blue.

So, the number of ways in which we can create a factorfic number is determined by the following cases:

  • The number 2 is blue and the number 3 is blue: In this case we have 1 option for number 1, one for number 2 and 1 for number 3. Taking into account that the number 2 and 3 are blue, if the number 4 and 6 are blue or red doesn't change the fact that the coloring is going to be factorific. So, we have two options for number 3 and 2 options for number 6. Finally the color of the number 5 is independent of the colors of number 2 and 3, so we also have 2 options for coloring number 5 and the coloring is going to be factorific. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>          2   </u>  *<u>         2    </u>* <u>    2          </u>=   8

number 1    number 2    number 3   number 4  number 5  number 6

At the same way we can calculate the following cases:

  • The number 2 is blue and the number 3 is red:  If the number 3 is red, the coloring is only going to be factorific is number 6 is red. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>          2   </u>  *<u>         2    </u>* <u>    1          </u>=  4

number 1    number 2    number 3   number 4  number 5  number 6

  • The number 2 is red and the number 3 is red:  If the number 2 and 3  are red, the coloring is only going to be factorific is number 4 and 6 are red. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>           1   </u>  *<u>         2    </u>* <u>    1          </u>=  2

number 1    number 2    number 3   number 4  number 5  number 6

  • The number 2 is red and the number 3 is blue:  If the number 2 is red, the coloring is only going to be factorific is number 4 is red. Then the number of ways for this situation is calculate as:

<u>   1           </u>*<u>        1          </u>*  <u>   1           </u> * <u>          1   </u>  *<u>         2    </u>* <u>    2          </u>=  4

number 1    number 2    number 3   number 4  number 5  number 6

If we sum all the cases, we obtain 18 ways to make a factorific coloring. So the probability can be calculated as:

P= \frac{18}{64} =  0.28125

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21/28 

comment for more help if you need it for future problems

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