Answer:
1 gamma = 15/8 alphas
Step-by-step explanation:
so we start by finding out what 1 gamma and 1 beta equals.
we know 4 gammas = 5 betas so if we divide by four on both sides we get:
1 gamma = 5/4 betas. we can apply that same procedure to 2 betas = 3 alphas and get 1 beta = 3/2 alphas
we know that 1 gamma = 5/4 betas and 1 beta = 3/2 alphas so how many alphas = 5/4 betas? using a proportion of ((3/2)/1) = ((x)/(5/4)) we can find that 5/4 betas = 15/8 alphas
therefore we know 1 gamma = 15/8 alphas or 1 and 7/8 alphas
Answer:
c = $5,400
Step-by-step explanation:
Given:
c = 0.9s
where,
s = amount sold
c = commission on sales
How much commission will he or she earn if the amount sold is $6,000?
Find c when she = $6,000
c = 0.9s
= 0.9 × 6,000
= 5,400
c = $5,400
(c, s) (5400, 6000)
Note: In option A, it should be "+" instead of "(".
Given:
The expression is

To find:
The equivalent expression.
Solution:
We have,

Using distributive property, we get


On combining like terms, we get


The expression
is equivalent to the given expression.
Therefore, the correct option is A.
The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.
Step-by-step explanation:
The given is,
In ΔWXY, ∠Y=90°
XW = 53
YX = 28
WY = 45
Step:1
Ref the attachment,
Given triangle XWY is right angled triangle.
Trigonometric ratio's,
∅
For the given attachment, the trigonometric ratio becomes,
∅
.....................................(1)
Let, ∠X = ∅
Where, XY = 28
XW = 53
Equation (1) becomes,
∅ 
∅ = 0.5283
∅ =
(0.5283)
∅ = 58.109°
Result:
The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.
Answer:
and 
Step-by-step explanation:
Given
5 daises to 2 roses
Required
Determine the relationship between them
The question shows a direct proportion between number of daises and roses.
i.e.

Where d = daises and r = roses
Convert the above expression to an equation

Make k the subject

When d = 5 and r = 2;


So, the first relationship between d and r can be gotten by substituting 2.5 for k in d = kr
So:

----------- (1)
Make r the subject in (1)
------------------------(2)
Hence, the relationships between d and r are:
and 