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3 years ago

Solution(atb) ²-2ab

Mathematics

2 answers:

Lapatulllka [165]3 years ago

8 0

Answer:

Step-by-step explanation:

a*a+2ab+b*b-2ab

a*a+b*b

It will be nice if you give me brainliest. Good luck!

BlackZzzverrR [31]3 years ago

4 0

Answer:

=a2b2t2−2ab

Step-by-step explanation:

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URGENT PLEASE HELP. CORRECT ANSWERS GETS BRAINLIST

horrorfan [7]

Answer: 1.601 × 10^-1

Step-by-step explanation: 1 minute = 60 seconds or 1 second = 1/60 minutes

9.63 seconds = 9.63/60 minutes

9.63/60 = 963/6x1000 = 321/2x1000

=160.1/1000=1.601/10 = 1.601 x 10^-1 minutes :)

4 0

2 years ago

Paired t-test Application (Part 1)An environmental engineer is tasked with determining whether a power plant cooling system is h

qaws [65]

Complete Question

The complete question is shown on the first and second uploaded image

Answer:

Part 1

The correct option is B

Part 11

The correct option is H

Step-by-step explanation:

From the question we are told that

The sample size is n = 15

Generally the sample mean for the input temperature is mathematically represented as

$\= x _1 = \frac{\sum x_i}{n}$

$\= x _1 = \frac{57.6 + 68.9 \cdots +60.4 }{15}$

$\= x _1 = 62.57$

Generally the sample mean for the output temperature is mathematically represented as

$\= x _2 = \frac{\sum x_i}{n}$

$\= x _2 = \frac{65.1 + 74.4 \cdots +67.3 }{15}$

$\= x _2 = 55.97$

Generally the difference between the mean of the input temperature and that of the output temperature is

$d = \= x_1 - \= x_2$

=> $d = 62.57 - 55.97$

=> $d = 6.6$

Generally the standard deviation of the difference between the input temperature and the output temperature is mathematically represented as

$s_d = \sqrt {\frac{1}{n-1 } \sum [d_i - d]^2}$

=> $s_d = \sqrt{\frac{[(57.6 - 65.1) - 6.6]^2+[(68.9 - 74.4) - 6.6]^2+ \cdots +[(68.1 - 74.7) - 6.6]^2 }{15-1} }$

=> $s_d = 1.732$

The null hypothesis is $H_o : \mu_1 -\mu_2 = 6$

The alternative hypothesis is $H_a : \mu _1 - \mu_2\ne 6$

Generally the test statistics is mathematically represented as

$t = \frac{d - 6}{ \frac{s_d}{ \sqrt{n} } }$

$t = \frac{6.6- 6}{ \frac{1.732}{ \sqrt{15} } }$

$t = 1.342$

Generally the p-value is mathematically represented as

$p-value = 2 * P(t > 1.342)$

From the student t distribution table( reference - danielsoper(dot)com(slash)statcalc(slash)calculator) at a degree of freedom of df = n-1 = 15-1 = 14

$P(t > 1.342) = t_{1.342 , 14} = 0.100478$

$p-value = 2 * 0.100478)$

$p-value = 0.201$

From the values obtained we see that the $p-value > \alpha$ hence the decision rule is fail to reject the null hypothesis

The conclusion is

The cooling system changes the temperature of the water by 6 degrees.

5 0

4 years ago

What is the answer to this?

Digiron [165]

The answer would be distributive property:)

6 0

3 years ago

Read 2 more answers

A variety pack of chocolates contains chocolate candies with different fillings. one eighth of the candy has coconut filling, 5/

tino4ka555 [31]

<u>Answer</u> : the number of candies having chocolate cream filling $=26$

Percent of candy has peanut butter filling = 31.25%

Fraction of candy is orange or chocolate cream = $\frac{9}{16}$

<u>Explanation:</u>

Part of candy has coconut filling = $\frac{1}{8}$

Part of candy has peanut butter filling = $\frac{5}{16}$

Part of candy has orange cream filling = $\frac{5}{32}$

Remaining will be chocolate cream filling

= $1-\frac{1}{8}-\frac{5}{16}-\frac{5}{32}\\=1-\frac{4+10+5}{32}\\=1-\frac{19}{32}\\=\frac{32-19}{32}\\=\frac{13}{32}$

Now, we have number of candies with coconut filling =8

so, $\frac{1}{8}\times x=8$ , where x is the total number of candies ,

x = 8×8=64

So, the number of candies having chocolate cream filling=

$\frac{13}{32}\times 64\\=26$

Percent of candy has peanut butter filling = $\frac{5}{16}\times 100\\=\frac{125}{4}$

∴Percent of candy has peanut butter filling = 31.25%

Fraction of candy is orange or chocolate cream

$=\frac{5}{32}+\frac{13}{32}\\=\frac{18}{32}\\=\frac{9}{16}$

∴Fraction of candy is orange or chocolate cream = $\frac{9}{16}$

8 0

3 years ago

I will mark you if you help me

Paraphin [41]

Slope intercept form: y=-0.25x+2.5

Graph shown below

7 0

3 years ago

Solution(atb) ²-2ab​

Solution(atb) ²-2ab