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irakobra [83]
3 years ago
7

What is the midpoint of (0,0) and (-8,6)

Mathematics
1 answer:
Alik [6]3 years ago
8 0
To find the midpoint, add the x values and divide by two, and add the y values and divide by two:
x = \frac{(0 +  - 8)}{2} \\ y =  \frac{(0 + 6)}{2}
Therefore, the midpoint of these two points is (-4,3)
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Three angles fits exactly around a point. Two of the angles are equal.The diffrence between the largest and the smallest angle i
IrinaK [193]

Answer:

The angles are 110, 110 and 140

Step-by-step explanation:

Let the equal angles be x.

So we have angles x, x and another third one

Now, the other third angle is 30 degrees larger than x, this means that the other third angle is 30 + x

Since they are angles at a point, adding the three together will make or give 360.

Thus,

x + x + x + 30 = 360

3x + 30 = 360

3x = 360-30

3x = 330

x = 330/3

x = 110

So the other third angle is 110 + 30 = 140

So the angles are 110, 110 and 140

3 0
3 years ago
According to the fundamental theorem of algebra, how many zeros does the polynomial below have?
Tom [10]

Answer:According to Apex the answer is 5

8 0
3 years ago
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mrs. Hudson invested $700 into an account that draws 3% interest, compounded annually. what is the total value of the account af
nadezda [96]
700 x .03 x 20 = 420
420 + 700
1120 is in the account after 20 years
7 0
3 years ago
Csc2theta=csctheta/2costheta<br><br>Can you help verify the identity
Yakvenalex [24]

csc(2x) = csc(x)/(2cos(x))

1/(sin(2x)) = csc(x)/(2cos(x))

1/(2*sin(x)*cos(x)) = csc(x)/(2cos(x))

(1/sin(x))*1/(2*cos(x)) = csc(x)/(2cos(x))

csc(x)*1/(2*cos(x)) = csc(x)/(2cos(x))

csc(x)/(2*cos(x)) = csc(x)/(2cos(x))

The identity is confirmed. Notice how I only altered the left hand side (LHS) keeping the right hand side (RHS) the same each time.

7 0
3 years ago
Please help meeeeeeeeeeeeeee
galina1969 [7]
Together they scored:
(3x+2)+(300-2x)=347
x+302=347
x=45
Substituting x:
3*45+2=135+2=137
300-2*45=300-90=210
So Makayla scored a total of 210 points
7 0
3 years ago
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