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Tanzania [10]
3 years ago
8

I don’t understand how to do #6

Mathematics
1 answer:
katrin2010 [14]3 years ago
8 0

A={0,2,4,6}, C={1,3,5,7}

A∩C, means that we need to find the same number in A and C. We can see that there are no the same numbers in set A and set C,

so A∩C=∅, empty set of numbers.

BU(A∩C)

"U" means that set will include all numbers of the set B and set (A∩C). Because A∩C=∅, empty set of numbers, (A∩C) does not have any numbers, so

BU(A∩C) includes only numbers of the set B.

So, BU(A∩C)={1,2,3,4,5}.

Answer is {1,2,3,4,5}.

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4 0
3 years ago
Read 2 more answers
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
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Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
3 years ago
Two welders worked a total of 46 h on a project. One welder made $34/h, while the other made $39/h. If the gross earnings of the
Ratling [72]

Answer:

25 and 21 hours respectively

Step-by-step explanation:

Let the number of hours worked by each welder be x and y respectively.

They worked a total of 46 hours. This means :

x + y = 46 hours.......(I)

Now, given their hourly charges, since we have the total amount of money realized, we can make an equation out of it. This means:

34x + 39y = 1669........(ii)

We then solve both simultaneously. From I, x = 46 -y

We can substitute this into ii

34(46 -y) + 39y = 1669

1564 -34y + 39y = 1669

5y = 1669 - 1564

5y = 105

y = 105/5 = 21

x = 46 - y

x = 46 - 21 = 25 hours

The numbers of hours worked by the welders are 25 and 21 respectively

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3 years ago
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What type of math is this problem? Is it advanced?

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