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sdas [7]
3 years ago
9

A board game has 25 cards, each printed with a number from 1 through 25. Sameer shuffled the cards, and then selected 1 card.

Mathematics
2 answers:
Inessa05 [86]3 years ago
8 0
We have to find the probability that one randomly selected card has a number less than 4 or a multiple of 9. There are numbers : 1 - 25. Numbers less than 4 are: 1, 2, and 3. Multiples of 9 that are less than 25 are : 9 ( 9 * 1 ) and 18 ( 9 * 2 ). So there are 5 favourable outcomes and 25 possible outcomes. The probability is: P ( A ) = ( number of favourable outcomes ) / ( number of possible outcomes ) = 5 / 25 = 1 / 5 = 0.2. Answer: The probability is 0.2 or 20 %<span>. </span>
telo118 [61]3 years ago
7 0
The correct answer is:      1/5
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What additional information could be used to prove ABC MQR using SAS?
Igoryamba

Answer:

To prove that ΔABC ≅ ΔMQR using SAS, we show that two sides with the intersection angle are congruent.

From the diagram, it is shown that CA is congruent to RM.

From the first option, given that m∠A = 64° and AB = MQ = 31 cm, then we have CA = RM, AB = MQ, and CAB = RMQ (i.e. m∠A = m∠M = 64°).

This shows that the first option is correct.

From the second option, given that CB = MQ = 29 cm, then we have CA = RM, CB = MQ, but ACB is not congruent to RMQ.

Thus the second option in not correct.

From the third option, m∠Q = 56° and CB ≅ RQ, then we have CA = RM, CB = RQ, ACB = 60°, but we do not know the value of MRQ.

Thus the third option is not correct.

From the fourth option, m∠R = 60° and AB ≅ MQ, then we have CA = RM, AB = MQ, RMQ = 64°, but we do not know the value of CAB.

Thus the fourth option is not correct.

From the fifth option, AB = QR = 31 cm, then we have CA = RM, AB = QR, but we do not know the value of CAB or MRQ.

Thus, the fifth option is not correct.

Therefore, the additional information that could be used to prove ΔABC ≅ ΔMQR using SAS is m∠A = 64° and AB = MQ = 31 cm

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