Given:
Area of a right triangle = 18 sq. inches
Length of one leg = 6 inches
To find:
The length of another leg.
Solution:
We know that, the area of a triangle is
In a right angle triangle, the area of the triangle is
Putting A=18 and 
, we get
Divide both sides by 3.
Both legs are equal so the given triangle is an isosceles right triangle.
If the triangle is not isosceles triangle, then the length of legs are factors of 36 because half of 36 is 18.
Therefore, the possible pairs of legs are 1 and 36, 2 and 18, 3 and 12, 4 and 9, 6 and 6, 9 and 4, 12 and 3, 18 and 2, 36 and 1.
$69 ÷ 6 = 11.5 per DVD
11.5 × 4 = 46
Answer:
69
Step-by-step explanation:
so x2 will give you 9 times 7 which is 63. add it to 2 times 3 which is 63 + 6 will give you 69.
Answer:
On occasions you will come across two or more unknown quantities, and two or more equations
relating them. These are called simultaneous equations and when asked to solve them you
must find values of the unknowns which satisfy all the given equations at the same time.
Step-by-step explanation:
1. The solution of a pair of simultaneous equations
The solution of the pair of simultaneous equations
3x + 2y = 36, and 5x + 4y = 64
is x = 8 and y = 6. This is easily verified by substituting these values into the left-hand sides
to obtain the values on the right. So x = 8, y = 6 satisfy the simultaneous equations.
2. Solving a pair of simultaneous equations
There are many ways of solving simultaneous equations. Perhaps the simplest way is elimination. This is a process which involves removing or eliminating one of the unknowns to leave a
single equation which involves the other unknown. The method is best illustrated by example.
Example
Solve the simultaneous equations 3x + 2y = 36 (1)
5x + 4y = 64 (2) .
Solution
Notice that if we multiply both sides of the first equation by 2 we obtain an equivalent equation
6x + 4y = 72 (3)
Now, if equation (2) is subtracted from equation (3) the terms involving y will be eliminated:
6x + 4y = 72 − (3)
5x + 4y = 64 (2)
x + 0y = 8
