All categories

3 years ago

I will mark brainlest please help!!!!

Mathematics

1 answer:

trasher [3.6K]3 years ago

4 0

Answer:

m∠T = 45°

Step-by-step explanation:

The sum of angles in a triangle is 180°.

∠S + ∠T + ∠U = 180°

2x + 10 + 3x - 9 + 6x - 19 = 180

11x - 18 = 180

11x = 180 + 18

= 198

x = 198 ÷ 11

x = 18

m∠T = 3x - 9

= 3(18) - 9

= 54 - 9

m∠T = 45°

You might be interested in

Is 5/10 and 8/18 proportional

salantis [7]

5/10 = 1/2

8/18 = 4/9

1/2 > 4/9

They're not proportional.

5 0

3 years ago

Read 2 more answers

Which of these equations represents a line parallel to the line 2x + y = 6?

laila [671]

Answer:

D) y= -2X+1

Step-by-step explanation:

All of the lines are perpendicular to the line 2x+y=6 except for D) y= -2X+1.

8 0

3 years ago

3x + 2y = 14. X + y = 5. Work put the values of x and y

andrey2020 [161]

Answer:

x = 4 , y = 1

Step-by-step explanation:

3x + 2y = 14 → (1)

x + y = 5 → (2)

Multiplying (2) by - 2 and adding to (1) will eliminate the y- term

- 2x - 2y = - 10 → (3)

Add (1) and (3) term by term to eliminate y

x = 4

Substitute x = 4 into (2) and evaluate for y

4 + y = 5 ( subtract 4 from both sides )

y = 1

7 0

2 years ago

PLEASE HELP ASAP 35 PTS

Nadusha1986 [10]

For questions 10 it c

8 0

3 years ago

Read 2 more answers

30 POINTS AVAILABLE

kherson [118]

Answer:

$\large\boxed{(x-2)^2+(y-1)^2=34}$

Step-by-step explanation:

The equation of a circle in standard form:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1$

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points (2, 1) and (5, -4):

$r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}$

Finally we have:

$(x-2)^2+(y-1)^2=(\sqrt{34})^2$

3 0

3 years ago