Answer:
2
Step-by-step explanation:
We are given the distance QA=1.25 and QA'=2.5.
We make the relation 2.5/1.25=2 is the scale factor!
Let's solve your equation step-by-step.
<span>0=<span>4+<span>n/5
</span></span></span>Step 1: Simplify both sides of the equation.<span>0=<span><span><span>1/5</span>n</span>+4
</span></span>Step 2: Flip the equation.<span><span><span><span>1/5</span>n</span>+4</span>=0
</span>Step 3: Subtract 4 from both sides.<span><span><span><span><span>1/5</span>n</span>+4</span>−4</span>=<span>0−4
</span></span><span><span><span>1/5</span>n</span>=<span>−4
</span></span>Step 4: Divide both sides by 1/5.<span><span><span><span>1/5</span>n/</span><span>1/5 </span></span>=<span><span>−4/</span><span>15</span></span></span><span>n=<span>−20
</span></span>Answer:<span>n=<span>−<span>20</span></span></span>
Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
9514 1404 393
Answer:
3, 0, 2, -2
Step-by-step explanation:
Put x=2 into each equation and solve for y.
<u>2 + y = 5</u>
y = 5 -2
y = 3
<u>3x +2y = 6</u>
3·2 +2y = 6
2y = 6 -6 = 0
y = 0
<u>2x +y = 6</u>
2·2 +y = 6
y = 6 -4
y = 2
<u>5x +3y = 4</u>
5·2 +3y = 4
3y = 4 -10 = -6
y = -2
Answer:
b for me hehe ok
Step-by-step explanation:
Explanation
