X^2-8x-7=0 Add 7 to both sides X^2-8x=7 Now use formula (B/2a)^2 (-8/2)^2= 16 Add 16 to left subtract from right to get X^2-8x+16=-9 Now factor into (X-4)^2=-9 For your final answer
So in your circle their is a terminal point who is assigned by the value of P(x,y) and lies or determined by teh value of T=4pi/3. To get the coordinates of this terminal point first is to know what is the angle of the T and the answer is (-1/2, -sqrt(3)/2)
