A line contains the points (8, 9) and (–12, –7). Using point-slope form, write the equation of the line that is parallel to the given line and that passes through (–5, –15).
2 answers:
For the answer to the question above, The slope of the line of the line is calculated through the equation, m = (y2 - y1) / (x2 - x1) Using the first two points in the given, m = (-7 - 9) / (-12 - 8) = 4/5 The line parallel to this has also a slope of 4/5. Through the point-slope form, the equation of the second line is, y - -15 = (4/5)(x - -5) Simplifying gives the answer of, y = (4/5)x -11 Eliminating the fraction, 5y = 4x - 55 I hope my answer helped you.
Hello there. <span>A line contains the points (8, 9) and (–12, –7). Using point-slope form, write the equation of the line that is parallel to the given line and that passes through (–5, –15). </span>m = (y2 - y1) / (x2 - x1)
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Answer:
-2
Step-by-step explanation:
Subtract 10 on both sides:
6x +10= -2
-10 -10
6x = -12
Divide by 6 on both sides:
6x = -12
/6 /6
x = -2
8/5:P hope i helped hehehe