Can someone help Solve these 2 questions for me? It's about Slope Intercept Forms.
1 answer:
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We can figure this out using the explicit formula.
n represents the term we are looking for.f(1) represents the first term in the sequence, which in this case, is -242.d represents the common difference, which in this case, is -9.
f(n) = -242 + -9(n - 1)
f(n) = -242 - 9n + 9
f(n) = -233 - 9n
Now, we can input 28 for n and solve.
f(28) = -233 - 9(28)
f(28) = -233 - 252
f(28) = -485
The 28th term of the sequence is -485.
n represents the term we are looking for.f(1) represents the first term in the sequence, which in this case, is -242.d represents the common difference, which in this case, is -9.
f(n) = -242 + -9(n - 1)
f(n) = -242 - 9n + 9
f(n) = -233 - 9n
Now, we can input 28 for n and solve.
f(28) = -233 - 9(28)
f(28) = -233 - 252
f(28) = -485
The 28th term of the sequence is -485.
Answer
Find out the altitude of the equilateral triangle .
To proof
By using the trignometric identity.
As shown in the diagram
and putting the values of the angles , base and perpendicular
solving
As
put in the above
a = 4 × 3
a = 12 units
The length of the altitude of the equilateral triangle is 12 units .
Option (F) is correct .
Hence proved