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julsineya [31]
3 years ago
9

PLEASE HELP! A class has an average score of 75%. A test is taken with an average score of 60%. The test is graded on a curve so

that 60%=75%. If Emalie's original score is 72%, what is her new grade after the curve? This is real life, as I'm trying to figure out my exam grade believe it or not!​
Mathematics
1 answer:
lord [1]3 years ago
7 0

Answer:

1.032%

Step-by-step explanation:

You might be interested in
Round the numbers to the nearest cent and then to the nearest dollar. 23. $62.756 24. $38.415
MrMuchimi

Answer:

23.  $ 62.76  to the nearest cent

      $63.00 to the nearest dollar

24.  $ 38.42  to the nearest cent

      $38.00 to the nearest dollar

Step-by-step explanation:

When we round to the nearest cent we round the second number after the decimal.  We look at the third number after the decimal.  If it is 5 or above we round up.

When we round to the nearest dollar, we round the number befroe the decimal. We look at the number after the decimal.  If it is 5 or above we round up.

23.  $62.756  we round the 5 so we look at the 6   6>= 5  so we round up

         $ 62.76  to the nearest cent

    $62.756  we round the 2 so we look at the 7  7>= 5  so we round up

          $63.00 to the nearest dollar

24. $38.415 we round the 1 so we look at the 5   5>= 5  so we round up

         $ 38.42  to the nearest cent

    $38.415  we round the 8 so we look at the 4  4< 5  so we leave alone

          $38.00 to the nearest dollar

6 0
4 years ago
In each diagram, ∆ABC has been transformed to yield ∆A'B'C'. Which transformation could NOT be achieved by rotation alone?
max2010maxim [7]

The ∆ABC has been transformed to yield ∆A'B'C'. The fourth diagram shows that the transformation could NOT be achieved by rotation alone.

The diagram is attached with the answer below:-

<h3 /><h3>What is dilation?</h3>

Dilation is the process of increasing the size of an object while maintaining its shape. Depending on the scale factor, the object's size can be increased or decreased.

In the first figure, ∆ABC has been transformed to yield ∆A'B'C' by rotation of 180 degrees either clockwise or counterclockwise along the midpoint of AB.

The second and third figures are the same. In both figures, ∆ABC has been transformed to yield ∆A'B'C' by rotation of 180 degrees either clockwise or counterclockwise along with the origin.

In the fourth figure, ∆ABC has been transformed to yield ∆A'B'C' by rotation of 180 degrees either clockwise or counterclockwise along with the origin.

But only in the fourth figure, ∆ABC has been transformed to yield ∆A'B'C' by reflection along the x-axis.

Therefore, the correct option is the 4th diagram.

To know more about dilation follow

brainly.com/question/3457976

#SPJ1

5 0
3 years ago
Three is a zero of the equation x^3-4x^2-3x+18=0
mylen [45]

Answer:

You did not list any choices but that factors into:

(x +2) * ( x -3) * (x -3) = 0

Making the "zeroes" -2, 3 and 3

Step-by-step explanation:


3 0
3 years ago
A study of the effects of acid rain on trees in the Hopkins Forest shows that 25 of 100 trees sampled exhibited some sort of dam
Grace [21]

Answer:

Yes

Step-by-step explanation:

We can test this claim using the one proportion z test :

x = 25 ; n = 100

Phat = x / n = 25 / 100 = 0.25

H0 : P = 0.15

H0 : P > 0.15

The test statistic :

Z = (phat - p) ÷ √p(1-p)/n

Z = (0.25-0.15) ÷ √(0.15*0.85)/100

Z = 2.8

Using the Pvalue from Zscore calculator :

α = 0.05

Pvalue (Z < 2.8) =0.0026

Pvalue < α ; We reject the Null

5 0
3 years ago
Lori creates the following design for a T-shirt.
kakasveta [241]

<u>Solution-</u>

From the figure,

AE = 2.4

EB = 2.8

BC = 11.7


Area of rectangle 1 = 8.68 sq.in

\Rightarrow FH \times HI=8.68

\Rightarrow EB \times HI=8.68  (∵ sides of the rectangle 2)

\Rightarrow 2.8 \times HI=8.68

\Rightarrow HI=3.1


Area of Triangle 1 = 6.48 sq.in

\Rightarrow \frac{1}{2}\times AE \times EG= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+FG)= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+HI)= 6.48  (∵ sides of the rectangle 1)

\Rightarrow EF+3.1= 5.4

\Rightarrow EF=2.3

\Rightarrow BH=2.3  (∵ sides of the rectangle 2)


BC = BH+HI+IC

\Rightarrow 11.7= 2.3+3.1+IC

\Rightarrow IC=6.3


The area of Rectangle 2,

=EB\times BH =2.8\times 2.3=6.44\ sq.in


The area of Triangle 2,

\frac{1}{2}\times GI \times IC=\frac{1}{2}\times EB \times IC=\frac{1}{2}\times 2.8 \times 6.3=8.82\ sq.in


The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2

= 6.48+8.68+8.82+6.44=30.42 sq.in


6 0
3 years ago
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