With digits 8, 5, and 6, an odd number must end in 5.
So far, we have _ _ 5.
The 8 is in the hundreds place.
Now we have 8_5.
The only place left for the 6 is the tens place.
The number is 865.
8 x 2 + 6x + 5=0
16 + 6x + 5=0
6x+21=0
6x+21-21=0-21
6x=-21
6x/6=-21/6
x=-7/2
Answer:
∴Given Δ ABC is not a right-angle triangle
a= AB = √45 = 3√5
b = BC = 12
c = AC = √45 = 3√5
Step-by-step explanation:
Given vertices are A(3,3) and B(6,9)

AB = 
Given vertices are B(6,9) and C( 6,-3)
= 
BC = 12
Given vertices are A(3,3) and C( 6,-3)

AC² = AB²+BC²
45 = 45+144
45 ≠ 189
∴Given Δ ABC is not a right angle triangle
Y = -2x^2
h = Xv = -B/2A = 0/-4 = 0.
k = -2*0^2 = 0.
V(0,0).
Use the following points for graphing:
Y = -2x^2.
(x,y)
(-2,-8)
(-1,-2)
V(0,0)
(1,-2)
(2,-8)
Y = -2x^2 + 4.
h = Xv = -B/2A = 0/-4 = 0.
k = Yv = -2*0^2 + 4 = 4.
V(0,4).
(-2,-4)
(-1,2)
V(0,4)
(1,2)
(2,-4)
Answer:
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Step-by-step explanation:
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