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solniwko [45]
3 years ago
10

The isotope cobalt-60 has a nuclear mass of 59.933820 u

Mathematics
1 answer:
Lesechka [4]3 years ago
3 0
Cobalt has an atomic number (Z) of 27, which means the nuclei of all its isotopes have 27 protons. Cobalt 60 has an atomic mass of 60, so it has 60-27 = 33 neutrons.

The mass of 27 isolated protons plus the mass of 33 isolated neutrons would be:

27*(1.007825 u) + 33*(1.008665 u) = 60.497220 u

The actual mass of the nucleus of 60-Co is 59.933820 u.

Mass defect: 60.497220 u - 59.933820 u = 0.563400 u

The mass defect is equal to the binding energy of a nucleus.
using the fact that 1 u = 931.5 MeV/c^2

(0.563400 u)*(931.5 MeV/u) = 524.807 MeV

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there are 52 cards in a deck so the chance is a red card (or not a red card) is 26 out of 52.

Step-by-step explanation:

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An English teacher needs to pick 9 books to put on his reading list for the next school year, and he needs to plan the order in
Nikitich [7]

Answer:   4.37\times10^3

Step-by-step explanation:

Given : Number of choices for novels = 4

Number of choices for plays = 6

Number of choices for poetry books = 5

Number of choices for nonfiction books = 5

Total books =4+6+5+5=20

If he wants to include all 4 novels, then the number of books left to select = 9-4=5

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Then, the number of different reading schedules are possible :_

^4C_4\times^{16}C_5\\\\=\dfrac{4!}{4!(4-4)!}\times\dfrac{16!}{5!(16-5)!}\\\\=(1)\times\dfrac{16\times15\times14\times13\times12\times11!}{120\times11!}\\\\=4368=4.368\times10^3\approx4.37\times10^3

Hence, the required answer is 4.37\times10^3.

8 0
3 years ago
A city has a population of 230,000 people. suppose that each year the population grows by 3.5% . what will the population be aft
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5 0
3 years ago
The incorrect work of a student to solve an equation 2(y + 6) = 4y is shown below.
Lina20 [59]

Answer:

<h3>⇒ A. 2 should be distributed as 2y + 12, y = 6</h3>

Step-by-step explanation:

Here are the steps to solve this equation:

<u>Given:</u>

First step: 2(y+6)-4y

Use the distributive property.

<u>Distributive property:</u>

<h3>⇒ A(B+C)=AB+AC</h3>

2(y+6)

2*y=2y

2*6=12

2y+12

Isolate the term of y from one side of the equations.

2y+12=4y

Subtract by 12 from both sides.

2y+12-12=4y-12

Solve.

2y=4y-12

Then, you subtract by 4y from both sides.

2y-4y=4y-12-4y

Solve.

2y-4y=-2y

-2y=-12

Divide by -2 from both sides.

\sf{\dfrac{-2y}{-2}=\dfrac{-12}{-2}}

Solve.

Divide the numbers from left to right.

<u>Solutions:</u>

-12/-2=6

\Longrightarrow: \boxed{\sf{y=6}}

  • <u>Therefore, the correct answer is A. "2 should be distributed as 2y+12, y=6".</u>

I hope this helps. Let me know if you have any questions.

4 0
2 years ago
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Answer:

$157.45

Step-by-step explanation:

All the amounts provided in the question are supposed to be added as a fee, so if you add all the numbers you would get $157.45.

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