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emmainna [20.7K]
2 years ago
10

Eddie has already written 23 pages, and he expects to write 1 page for every additional hour spent writing. After spending 21 ho

urs writing this week, how many pages will Eddit have written in Total?​
Mathematics
2 answers:
padilas [110]2 years ago
8 0

Answer:

44

Step-by-step explanation:

1x21=21

21+23=44

Allushta [10]2 years ago
7 0

Answer:

He written 21 pages

Step-by-step explanation:

he wants to spend one hour on each page so if he spends 21 hours = 21 pages

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-c = 3abc-a; solve for c
emmainna [20.7K]

Answer:

C= 12

Step-by-step explanation:

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3 years ago
8+8- 19=??<br> pls help and thank u
kumpel [21]
-3 the answer is -3 ight
4 0
3 years ago
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-3( 2u + 5 ) +3.5u = -1u solve the equation
lora16 [44]

Answer:

that conclude idk

Step-by-step explanation:

-6U+-15+3.5U=-1U

-2.5U+15

4 0
3 years ago
Subtract 75% of 86 ft
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75% of 86ft would be 64.5
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3 0
2 years ago
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The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.
andrezito [222]

Answer:

Given the equation: 3x^2+10x+c =0

A quadratic equation is in the form: ax^2+bx+c = 0 where a, b ,c are the coefficient and a≠0 then the solution is given by :

x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a} ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}

Simplify:

x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}

Also, it is given that the difference of two roots of the given equation is 4\frac{2}{3} = \frac{14}{3}

i.e,

x_1 -x_2 = \frac{14}{3}

Here,

x_1 = \frac{-10 + \sqrt{100- 12c}}{6} ,     ......[2]

x_2= \frac{-10 - \sqrt{100- 12c}}{6}       .....[3]

then;

\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}

simplify:

\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}

or

\sqrt{100- 12c} = 14

Squaring both sides we get;

100-12c = 196

Subtract 100 from both sides, we get

100-12c -100= 196-100

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve x_1 , x_2

x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}

or

x_1 = \frac{-10 + \sqrt{100- 96}}{6} or

x_1 = \frac{-10 + \sqrt{4}}{6}

Simplify:

x_1 = \frac{-4}{3}

Now, to solve for x_2 ;

x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}

or

x_2 = \frac{-10 - \sqrt{100- 96}}{6} or

x_2 = \frac{-10 - \sqrt{4}}{6}

Simplify:

x_2 = -2

therefore, the solution for the given equation is: -\frac{4}{3} and -2.


3 0
2 years ago
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