[HELP ASAP] Triangle angles:

Dr. Thomas just started an experiment. She will collect data for 6 days. How many hours is this?

Ber [7]

6 days* 24 hours per day= 144 hours

Final answer: 144 hours

4 0

2 years ago

Read 2 more answers

I don’t know how to do this XD plzzzz help meh

AveGali [126]

Answer:

D) 5/2 divided by 8/6

Step-by-step explanation:

3 0

2 years ago

Solve the equation.

Vinil7 [7]

If you would like to solve the equation x + 1/6 = 6, you can do this using the following steps:

x + 1/6 = 6 /-1/6
x + 1/6 - 1/6 = 6 - 1/6
x = 6 - 1/6
x = 36/6 - 1/6
x = 35/6
x = 5 5/6

The correct result would be C. x = 5 5/6.

5 0

2 years ago

Hat is the solution to the equation 3/3(4c + 16)=2c+9 ?<br><br> c =

marusya05 [52]

If it is $\frac{3}{3(4c+16)}$ =2c+9, go to AAAAAA
if it is ( $\frac{3}{3}$ )(4c+16)=2c+9, go to BBBBB

AAAAAAAAA
$\frac{3}{3(4c+16)}$ =2c+9
$\frac{1}{4c+16}$ =2c+9
times 4c+16 to both sides
1=(2c+9)(4c+16)
distribute
1=8c^2+68c+144
minus 1 both sides
0=8c^2+68c+143
use quadratic formula
c= $\frac{-17- \sqrt{3} }{4}$ or $\frac{-17+ \sqrt{3} }{4}$

BBBBBBBBBBBB
(3/3)(4c+16)=2c+9
1(4c+16)=2c+9
4c+16=2c+9
minus 2c both sides
2c+16=9
minus 16 both sides
2c=-7
divide both sides by 2
c=-7/2
c=-3.5

if it is $\frac{3}{3(4c+16)}$ =2c+9,
c= $\frac{-17- \sqrt{3} }{4}$ or $\frac{-17+ \sqrt{3} }{4}$

if it is ( $\frac{3}{3}$ )(4c+16)=2c+9, c=-3.5

7 0

3 years ago

Read 2 more answers

Need help simplifying this

diamong [38]

The simplified answer is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$ .

<u>Step-by-step explanation:</u>

$$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term $(\frac{3x+y}{3x+y})$ and 2nd term by $(\frac{z+2x}{z+2x})$

= $\frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= $\frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}$

Now, the denominators are same, you can subtract it.

= $\frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

= $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

Thus the simplified solution is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

4 0

3 years ago