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ycow [4]
2 years ago
11

PLEASEE HELP THIS IS A MAP TEST

Mathematics
2 answers:
torisob [31]2 years ago
3 0

Answer:

E. 10x + 50

Step-by-step explanation:

distrubution

5(2x) + 5(10)

10x + 50

Sedbober [7]2 years ago
3 0

Option E. 10x+50

Reason:-

5(2x + 10) \\  \\  =   10x + 50

<h3>Hope This Helps You ❤️</h3>
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This circle is centered at the orgin, and the length of it’s radius is 5. What is the ewuation of the circle?
pav-90 [236]
\bf \textit{equation of a circle}\\\\ &#10;(x- h)^2+(y- k)^2= r^2&#10;\qquad &#10;center~~(\stackrel{0}{ h},\stackrel{0}{ k})\qquad \qquad &#10;radius=\stackrel{5}{ r}&#10;\\\\\\&#10;(x-0)^2+(y-0)^2=5^2\implies x^2+y^2=25
8 0
3 years ago
Read 2 more answers
- is dilated to be ' ' ' '. The original is the center of dilation.
Oliga [24]
The scale factor is 5

In the first image, you can see that the pre image square it 1 unit long and the image is 5. How do you get 1 to 5, you multiply by 5. So the scale factor is 5.
7 0
3 years ago
IDK WHAT TO DO SOMEONE PLEASE EXPLAIN OR HELP
Zarrin [17]
Alright so, let’s break this down.

To find the first coordinate you need to solve the first equation

To do that you can do
6+9=15
So that mean 3x has to be equal to 15
You divide 15 by 3

The answer to that is the solution to the first equation, or the first coordinate.

For the second one, you know x has to be negative because the solution is negative

2x is going to have to equal -20
-20/2 gets you the solution

Remember that it will be negative
You now have both of the coordinates

You take coordinate A and technically add coordinate B to it
You do that because B is negative and A is positive
Then you have the answer to c
6 0
3 years ago
Pls help :)) this question is confusing for me :)
Temka [501]

Given:

y^{2}(2 y-5)-8 y+20

To find:

The product of the expression.

Solution:

y^{2}(2 y-5)-8 y+20=y^{2}(2 y-5)+(-8 y+20)

Take out -4 as a common factor in Last two terms.

                                =y^{2}(2 y-5)-4(2 y-5)

Make sure the terms in both brackets must be same.

Take out common factor (2y - 5) from both terms.

                                =(2 y-5)(y^{2}-4)

4 can be written as 2².

                                =(2 y-5)\left(y^{2}-2^2\right)

Using the identity: (a^2-b^2)=(a-b)(a+b)

                                =(2 y-5)(y-2)(y+2).

The product is (2 y-5)(y-2)(y+2).

5 0
3 years ago
What is the area of the walkway
alina1380 [7]

Answer:

missing info / cannot solve without the info needed

Step-by-step explanation:

6 0
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