The probabability of winning on at least 1 bet is equal to 1 less the probaility of not winning on either of the 6 bets.
The probability of not wining on any bet is independent of winning or not winning on any of the bets, so the combined probability is calculated as the product of each individual probability.
Each indivitual probability of not winning the is:
(number of not winning outcomes) / (number of possible outcomes) = 37 / 38.
Then, the combined probability of not winning the six times is: (1/38)*(37/38)*(37/38)*(37/38)*(37/38)*(37/38) =(37/38)^6
Therefore, the probability of winning at least one bet is:
= 1 - (37/38)^6 ≈ 1 - 0.973684 ≈ 0.03.
Answer: 0.03.
Answer:
There are many scenario's.
Step-by-step explanation:
1.4:5
2.4/5
3.4÷5
The answer is <span>C. 210 mi
</span>
The velocity (v) is distance (d) divided by time (t):
v = d/t
v = 60 mph
t = 3 1/2 h = 3.5 h
d = ?
d = v * t
d = 60 * 3.5 = 210 mi
You need to include the image of the question it doesn’t make sense if
Yes, it does! evaluating and solving an expression are the same thing!
