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2 years ago

Evaluate: 6(3)(x + 1) Find f(4)

Mathematics

2 answers:

arlik [135]2 years ago

6 0

Answer:

18x+18

Step-by-step explanation:

anyanavicka [17]2 years ago

3 0

Answer:

18+18

Step-by-step explanation:

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Help due by 11 it 10 :55

belka [17]

Answer: 0.11

Step-by-step explanation: (2/3) / 6 = 0.11

4 0

3 years ago

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A watercolor painting is 24 inches long by 11 inches wide. Ramon makes a border around the watercolor painting by making a mat t

sergeinik [125]

Given: It is given that the length of the painting is 24 inches and the width is 11 inches.

To find: Area of the mat

Solution:

The watercolor painting is 24 inches long by 11 inches wide.

So, the area of the painting is:

$\text{Area of painting}=l\times b$

$\text{Area of painting}=24\times 11$

$\text{Area of painting}=264 \text{ in}^2$

The length of painting with mat is = 24 in + 3 in + 3 in = 30 in

The width of painting with mat = 11 in + 3 in + 3 in = 17 in

$\text{Area of painting with mat}=30\times 17$

$\text{Area of painting with mat}=510 \text{ in}^2$

Now to calculate the area of mat subtracts the area of painting from the area of the mat.

$\text{Area of mat}=\text{Area of painting with mat}-\text{Area of painting}\\$

$\text{Area of mat}=510-264$

$\text{Area of mat}=246 \text{ in}^2$

Hence, the area of the mat is 246 in².

6 0

3 years ago

Mister Rogers is fencing another new rectangular garden in his neighborhood. One side of the garden faces the road and needs to

Oksanka [162]

Answer:

length of the pretty side and length of the side oppositte to the pretty side = 37.91 ft

length of the other two sides = 27.52 ft

Step-by-step explanation:

The mathematical problem is:

Max A = b1*h

subject to: 35*b1 + 18*(2*h + b2) <= 3000

Where

A: area of the garden

b1: length of the pretty side

b2: length of the side oppositte to the pretty side

h: length of the other two sides

Replacing with b1 = b2 and taking only the equality sign in the restriction (in the maximum all the money will be spent), we get:

35*b1 + 18*(2*h + b1) = 3000

35*b1 + 36*h + 18*b1 = 3000

53*b1 + 36*h = 3000

b1 = 3000/53 - (36/53)*h

Substituing in Area's formula

A = (3000/53 - (36/53)*h)*h

A = (3000/53)*h - (36/53)*h^2

In the maximum, the derivative of A is equal to zero

dA/dh = 3000/53 - 2*(36/53)*h =

3000/53 - 72/35*h = 0

h = (3000/53)*(35/72)

h = 27.52 ft

then,

b1 = 3000/53 - (36/53)*27.52

b1 = 37.91 ft =b2

3 0

3 years ago

Heeeelllpppppp (THERE ARE FIVE QUESTIONS!!! LOOK AT ALL THE IMAGES

Andreyy89

Answer:

15cm^2

Step-by-step explanation:

area of rectangle

area = length x width

5cm x 3cm

15cm^2

4 0

3 years ago

How do I find the scale factor of this problem

ale4655 [162]

Match up each of the corresponding sides, and simplify the ratio.
That ratio is the scale factor.

5 0

3 years ago

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