1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nadya [2.5K]
3 years ago
12

Explain how you know weather to add or subtract when you use the distributive property to multiply

Mathematics
2 answers:
lana66690 [7]3 years ago
7 0
Use the phrase pemdas

it shows the order you solve. parenthesis, exponents, multiplication, division, addition, and then subtraction. ask me if you need any other help!
tester [92]3 years ago
6 0
You would know by how the problem is written for example if a equation is written like this (2+3)5 you add 2+3 first then multiply by 5 to get 25 therefore you add first
You might be interested in
Rewrite 9^4 * 10^4 as a single power
Vlada [557]

Answer:

90^8

Step-by-step explanation:

5 0
3 years ago
PLEASE THESE 2 HELPPPPPPPPPPPP
nirvana33 [79]

Answer:

c and g

Step-by-step explanation:

6 0
3 years ago
Hi guys, can anyone help me with this triple integral? Many thanks:)
Crank

Another triple integral.  We're integrating over the interior of the sphere

x^2+y^2+z^2=2^2

Let's do the outer integral over z.   z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

y^2=4-x^2-z^2

x is the inner integral so at this point we conservatively say its zero.  That means y goes from -\sqrt{4-z^2} and +\sqrt{4-z^2}

Similarly the inner integral x goes between \pm-\sqrt{4-y^2-z^2}

So we rewrite the integral

\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz

Let's work on the inner one,

\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz

There's no z in the integrand, so we treat it as a constant.

=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}

So the middle integral is

\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy  

I gotta go so I'll stop here, sorry.

7 0
3 years ago
Read 2 more answers
error uses 1/3 can of wet dog food for his dog,muddy,each day.how many servings will he get from 5 cans of dog food?
Vesnalui [34]
First convert 5 cans of dog food to a fraction
(5*3)/3 = 15/3
15/3 - 1/3 = 14/3
he uses 1/3 a can and so he then has 14 servings.
7 0
3 years ago
An equation is given.<br><br> Solve the equation for r.
goblinko [34]
There is not an equation
3 0
3 years ago
Other questions:
  • Can someone help me plzz !
    9·1 answer
  • HELLO!!! PLEASE HELP?! BRAINLIEST ANSWER INCLUDED! A sample of 130 firecrackers contained 9 duds. How many duds would you expect
    10·2 answers
  • What is the measure of JKL?
    8·2 answers
  • Erika calculated that she would spend $115 on school supplies this year. She actually spent $82.50 on school supplies. What is E
    7·2 answers
  • Ben walks 2 m from his desk to the teacher's desk. From the teacher's desk, he then walks 3 m in the same direction to the class
    12·2 answers
  • What is a formula for the nth term of the given sequence?<br> 36, 24, 16...
    15·1 answer
  • A line, line segment, or ray that intersects a line segment at its midpoint is a segment bisector. True or fals?
    6·2 answers
  • What is the domain and range?
    13·1 answer
  • Please help! I’ll give brainliest!
    10·1 answer
  • Can someone help me out with this?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!