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ale4655 [162]
3 years ago
7

Claire mowed 4 lawns last week. She mowed each lawn in startfraction 7 over 27 endfraction hour. She mowed the same lawns this w

eek in startfraction 5 over 27 endfraction hour each using her new lawn mower. How many times longer was​ claire's time to mow all the lawns last week than this​ week?
Mathematics
1 answer:
maw [93]3 years ago
6 0

Claire's time to mow all the lawns last week was 1.4 times longer than this week.

<em><u>Explanation</u></em>

Claire mowed each lawn in \frac{7}{27} hour last week.

So, the <u>total time taken to mow all 4 lawns last week</u> =\frac{7}{27}*4=\frac{28}{27} hours.

She mowed the same lawns this week and took \frac{5}{27} hour for each.

So, the <u>total time taken to mow all 4 lawns this week</u> =\frac{5}{27}*4=\frac{20}{27} hours.

Now.....

<u><em>(Total time in last week / Total time in this week)</em></u><em>  </em>=\frac{(\frac{28}{27})}{(\frac{20}{27})} = \frac{28}{20}=\frac{7}{5}=1.4

So, Claire's time to mow all the lawns last week was 1.4 times longer than this week.

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Tan(2 sin^-1 0.4)<br> Find the Exact value
stiv31 [10]

Answer:

tan(2u)=[4sqrt(21)]/[17]

Step-by-step explanation:

Let u=arcsin(0.4)

tan(2u)=sin(2u)/cos(2u)

tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]

If u=arcsin(0.4), then sin(u)=0.4

By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.

This also implies cos(u)=sqrt(0.84) since cosine is positive.

Plug in values:

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]

tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]

tan(2u)=[(40)(sqrt(0.84)]/[34]

tan(2u)=[(20)(sqrt(0.84)]/[17]

Note:

0.84=0.04(21)

So the principal square root of 0.04 is 0.2

Sqrt(0.84)=0.2sqrt(21).

tan(2u)=[(20)(0.2)(sqrt(21)]/[17]

tan(2u)=[(20)(2)sqrt(21)]/[170]

tan(2u)=[(2)(2)sqrt(21)]/[17]

tan(2u)=[4sqrt(21)]/[17]

7 0
3 years ago
[Grade 7 set 1]
Veseljchak [2.6K]

Step-by-step explanation:

No it would because you have to find the number for why and the two is the power so no it not going to be.

4 0
3 years ago
Read 2 more answers
Which two complex numbers that could have been added together to make -11+3i
irina [24]

Answer:

Step-by-step explanation:

There are an infinite number of possible solutions.

here's a few

(1 - 4i) + (-12 + 4i)

(-5.5 + 2i) + (-5.5 + i)

(-24 - 27i) + (13 + 30i)

3 0
3 years ago
If you answer this you are a certified cool kid
Oksana_A [137]

Answer:

60

Step-by-step explanation:

Im too lazy

180-117=63

3y+12+63+4y=180

7y+75=180

7y=105

y=15

4(15)=60

Can i get brainliest?

6 0
3 years ago
Read 2 more answers
Here are summary statistics for randomly selected weights of newborn​ girls: nequals202​, x overbarequals28.3 ​hg, sequals6.1 hg
Lorico [155]

Answer:

The confidence interval is 27.5 hg less than mu less than 29.1 hg

(A) Yes, because the confidence interval limits are not similar.

Step-by-step explanation:

Confidence interval is given as mean +/- margin of error (E)

mean = 28.3 hg

sd = 6.1 hg

n = 202

degree of freedom = n-1 = 202-1 = 201

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value corresponding to 201 degrees of freedom and 5% significance level is 1.97196

E = t×sd/√n = 1.97196×6.1/√202 = 0.8 hg

Lower limit = mean - E = 28.3 0.8 = 27.5 hg

Upper limit = mean + E = 28.3 + 0.8 = 29.1 hg

95% confidence interval is (27.5, 29.1)

When mean is 28.3, sd = 6.1 and n = 202, the confidence limits are 27.5 and 29.1 which is different from 27.8 and 29.6 which are the confidence limits when mean is 28.7, sd = 1.8 and n = 17

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4 years ago
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