Answer:
tan(2u)=[4sqrt(21)]/[17]
Step-by-step explanation:
Let u=arcsin(0.4)
tan(2u)=sin(2u)/cos(2u)
tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]
If u=arcsin(0.4), then sin(u)=0.4
By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.
This also implies cos(u)=sqrt(0.84) since cosine is positive.
Plug in values:
tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]
tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]
tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]
tan(2u)=[(40)(sqrt(0.84)]/[34]
tan(2u)=[(20)(sqrt(0.84)]/[17]
Note:
0.84=0.04(21)
So the principal square root of 0.04 is 0.2
Sqrt(0.84)=0.2sqrt(21).
tan(2u)=[(20)(0.2)(sqrt(21)]/[17]
tan(2u)=[(20)(2)sqrt(21)]/[170]
tan(2u)=[(2)(2)sqrt(21)]/[17]
tan(2u)=[4sqrt(21)]/[17]
Step-by-step explanation:
No it would because you have to find the number for why and the two is the power so no it not going to be.
Answer:
Step-by-step explanation:
There are an infinite number of possible solutions.
here's a few
(1 - 4i) + (-12 + 4i)
(-5.5 + 2i) + (-5.5 + i)
(-24 - 27i) + (13 + 30i)
Answer:
60
Step-by-step explanation:
Im too lazy
180-117=63
3y+12+63+4y=180
7y+75=180
7y=105
y=15
4(15)=60
Can i get brainliest?
Answer:
The confidence interval is 27.5 hg less than mu less than 29.1 hg
(A) Yes, because the confidence interval limits are not similar.
Step-by-step explanation:
Confidence interval is given as mean +/- margin of error (E)
mean = 28.3 hg
sd = 6.1 hg
n = 202
degree of freedom = n-1 = 202-1 = 201
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value corresponding to 201 degrees of freedom and 5% significance level is 1.97196
E = t×sd/√n = 1.97196×6.1/√202 = 0.8 hg
Lower limit = mean - E = 28.3 0.8 = 27.5 hg
Upper limit = mean + E = 28.3 + 0.8 = 29.1 hg
95% confidence interval is (27.5, 29.1)
When mean is 28.3, sd = 6.1 and n = 202, the confidence limits are 27.5 and 29.1 which is different from 27.8 and 29.6 which are the confidence limits when mean is 28.7, sd = 1.8 and n = 17