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Karo-lina-s [1.5K]
3 years ago
10

A telescope costs $126 with a 30% discount. What was the original price?

Mathematics
2 answers:
Rama09 [41]3 years ago
8 0

Answer:

$163.8

Step-by-step explanation:

We need to first make the 30% into a decimal. So it will be 0.30.

Then you need to multiply the 0.30 into 126  {  126 x 0.30 }

Which gives you 37.8

Then to fin the original you will need to add the $37.8 to $126

Which is $163.8

Since the discount price was $37.8 and they deducted that from the original price which gave you $126 the question said.

Check : <em>$126 + $37.8 = $163.8</em>

pychu [463]3 years ago
6 0

Answer:

$180

Step-by-step explanation:

Since the cost of the telescope with the 30% discount is $126 then $126 is 70% of the original price. Remember 100-30=70. To find the original price set up a proportion with these values:

\frac{126}{x}=\frac{70}{100}

Solve for the original price by cross multiplying numerator with denominator.

x(70) = 126(100)

70x = 12600

x= $180

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Answer:

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Step-by-step explanation:

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The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding
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Answer:

We conclude that the mean wedding cost is less than $30,000 as advertised.

Step-by-step explanation:

We are given the following data set:(in thousands)

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Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{236100}{8} = 29512.5

Sum of squares of differences = 3408750

S.D = \sqrt{\frac{3408750}{7}} = 697.82

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Sample size, n = 8

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Sample standard deviation, s = $ 697.82

First, we design the null and the alternate hypothesis

H_{0}: \mu = 30000\text{ dollars}\\H_A: \mu < 30000\text{ dollars} We use one-tailed t test to perform this hypothesis.

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t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

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t_{stat} < t_{critical}

We fail to accept the null hypothesis and reject it.

We conclude that the mean wedding cost is less than $30,000 as advertised.

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