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Sergeeva-Olga [200]

3 years ago

11

It takes 3.3 quarts to water 1 square foot of a vegetable garden, how many gallons does it take to water a garden 10 feet by 12

feet?
A 96
B 99
C 39.6
D 396

1 answer:

VashaNatasha [74]3 years ago

8 0

Answer:

i got c

Step-by-step explanation:

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Which sum or difference identity could be used to prove that sin(pie + q) = -sin q

Paladinen [302]

Answer:

see below

Step-by-step explanation:

<em><u>sin(a+b) = sin(a)cos(b) + cos(a)sin(b)</u></em>

sin(π+q) = sin(π)cos(q) + cos(π)sin(q)

sin(π) = 0

cos(π) = -1

therefore

sin(π+q) = 0*cos(q) -sin(q) = -sin(q)

7 0

3 years ago

what is the equation of a line in slope-intercept form having a slope of -3 and a y-intercept of -2?

lutik1710 [3]

Answer:

The equation is y=-3x-2

Step-by-step explanation:

The first we need to know is the equation of a line, and it is y=mx+b

where the m is the slope and b is the interception to the y axis

With the information in the question the slope is -3 and the equation thats equal to m. and the y intercept of -2 thats equal to the b value

then y=-3x-2

5 0

3 years ago

Please answer question three and four if you can :)<br> Show full working out ty;)

nikklg [1K]

Step-by-step explanation:

3

Let D be the mid point of side BC, [B(2, - 1), C(5, 2)].

Therefore, by mid-point formula:

$D = ( \frac{2 + 5}{2}, \: \: \frac{ - 1 + 2}{2} ) = ( \frac{7}{2}, \: \: \frac{ 1}{2} ) \\ \therefore D= (3.5, \: \: 0.5) \\ \& \: A=(-1,\:\:4)...(given) \\\\ now \: by \: distance \: formula \\ \\ Length \: of \: segment \: AD \\ = \sqrt{( - 1 - 3.5)^{2} + {(4 - 0.5)}^{2} } \\ = \sqrt{(4.5)^{2} + {(3.5)}^{2} } \\ = \sqrt{20.25 + 12.25 } \\ = \sqrt{32.5} \\ \red{ \boxed{\therefore Length \: of \: segment \: AD = 5.7 \: units}}$

4 (a)

Equation of line AB[A(2, 1), B(-2, - 11)] in two point form is given as:

$\frac{y-y_1}{y_1-y_2} =\frac{x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-1}{1-(-11)} =\frac{x-2}{2 - (-2) } \\\\\therefore \frac{y-1}{1+11} =\frac{x-2}{2 +2} \\\\\therefore \frac{y-1}{12} =\frac{x-2}{4} \\\\\therefore \frac{y-1}{3} =\frac{x-2}{1} \\\\\therefore y-1= 3(x - 2)\\\\\therefore y= 3x - 6+1\\\\\therefore y= 3x - 5\\\\ \huge \purple {\boxed {\therefore 3x - y-5=0}} \\$

is the equation of line AB.

Now we have to check whether C(4, 7) lie on line AB or not.

Let us substitute x = 4 & y = 7 on the Left hand side of equation of line AB and if it gives us 0, then C lies on the line.

$LHS = 3x - y-5\\=3\times 4-7-5\\= 12-12\\=0\\= RHS$

Hence, point C (4, 7) lie on the straight line AB.

4(b)

Like we did in 4(a), first find the equation of line AB and then substitute the coordinates of point C in equation and if they satisfy the equation, then all the three points lie on the straight line.

4 0

4 years ago

Please help me, this is like the easiest thing but I'm stuck

AlexFokin [52]

Answer: A. 384 sq. mm

Step-by-step explanation: The area for the square is 12x12 or 144. The area for a triangle is base x height x 1/2. Therefore, that would be 12 x 10 x 1/2 or 60. There are 4 sides to this pyramid, so 60 x 4 = 240. We then add 144 and 240 to get 384 sq. mm.

5 0

3 years ago

Which measure of center is the most appropriate for the data in Table 1 (Height) in Task 1? Give a reason for your answer.

Zigmanuir [339]

This isn’t an answer but we gotta see the question to answer it ☠️☠️

3 0

2 years ago

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