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Papessa [141]
3 years ago
7

What is the domain of the function y=%/x-1? O- o -1 < x < oo 0 O 1

Mathematics
1 answer:
LekaFEV [45]3 years ago
6 0

Answer:

-\infty < x < \infty

Step-by-step explanation:

Given

y = \sqrt[3]{x - 1}

Required

The domain

The given function is cubic root; there are no restrictions on cubic root functions

Hence, the domain is:

-\infty < x < \infty

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Jared earned $55 from cleaning pools. He deposits the $55 into his checking account.
TiliK225 [7]

Answer:

Jared transfers $55 to his checking account from his savings account.

Jared spends $55 from his checking account to purchase a college Algebra textbook

Jared withdraws $55 from his checking account

Hope this helps!

8 0
3 years ago
10 points pls answer ASAP
boyakko [2]

Answer:

145

Step-by-step explanation:

Its the opposite angle of 145

7 0
3 years ago
Answers for the 2 boxes please :)​
monitta

Answer:

x=1

y=2

Step-by-step explanation:

Multiply the second equation by 2

and then solve!

4 0
3 years ago
Read 2 more answers
For each trip, a taxi company charges a fixed fee of $2.00 plus $0.75 for each 1/2 mile or fraction of 1/2 miles. If, for every
nydimaria [60]

Answer:

E: 2.00 + 0.75 [ 2r]

Step-by-step explanation:

r represents the number of miles. For each 1/2 mile the taxi will charge and extra free of $0.75. Then, for each mile, the taxi will charge $0.75*2. For example:

For a trip of 1 mile the taxi will charge:

$2.00+$0.75*2

For a trip of 2 miles, the taxi will charge:

$2.00+0.75*4

For a trip of 10 miles, the taxi will charge:

$2.00+$0.75*20

Notice that the variable fee (the one that depends on the number of miles) is $0.75 times the double of miles. In each case the number of miles is multiplied by two. Then the correct answer is E: 2.00 + 0.75 [ 2r]

5 0
3 years ago
Evaluate the expression and write your answer in the form a + bi. 1) (2-6i)+(4+2i)2) (6+5i)(9-2i)3) 2/(3-9i)4) (3 − 5i)(7 − 2i)
laiz [17]

Answer:

Step-by-step explanation:

Given the following complex numbers, we are to expressed them in the form of a+bi where a is the real part and b is the imaginary part of the complex number.

1) (2-6i)+(4+2i)

open the parenthesis

= 2-6i+4+2i

collect like terms

= 2+4-6i+2i

= 6-4i

2)  (6+5i)(9-2i)

= 6(9)-6(2i)+9(5i)-5i(2i)

= 54-12i+45i-10i²

= 54+33i-10i²

In complex number i² = -1

= 54+33i-10(-1)

= 54+33i+10

= 54+10+33i

= 64+33i

3) For the complex number 2/(3-9i), we will rationalize by multiplying by the conjugate of the denominator i.e 3+9i

= 2/3-9i*3+9i/3+9i

=2(3+9i)/(3-9i)(3+9i)

= 6+18i/9-27i+27i-81i²

= 6+18i/9-81(-1)

= 6+18i/9+81

= 6+18i/90

= 6/90 + 18i/90

= 1/15+1/5 i

4) For (3 − 5i)(7 − 2i)

open the parenthesis

= 3(7)-3(2i)-7(5i)-5i(-2i)

= 21-6i-35i+10i²

= 21-6i-35i+10(-1)

= 21-41i-10

= 11-41i

4 0
3 years ago
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