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Papessa [141]
2 years ago
7

What is the domain of the function y=%/x-1? O- o -1 < x < oo 0 O 1

Mathematics
1 answer:
LekaFEV [45]2 years ago
6 0

Answer:

-\infty < x < \infty

Step-by-step explanation:

Given

y = \sqrt[3]{x - 1}

Required

The domain

The given function is cubic root; there are no restrictions on cubic root functions

Hence, the domain is:

-\infty < x < \infty

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Which of the following is not a possible number of solutions when solving a system of equations containing a quadratic and a lin
Kobotan [32]

Answer:

3

Step-by-step explanation:

We have a system with two equations, one equation is a quadratic function and the other equation is a linear function.

To solve this system we have to clear "y" in both equations, and then equal both equations, then we will have a quadratic function and equal it to zero:

ax^2+bx+c=0, a\neq 0

Then to resolve a quadratic equation we apply Bhaskara's formula:

x_{1}=\frac{-b+\sqrt{b^2-4ac} }{2a}

x_{2}=\frac{-b-\sqrt{b^2-4ac} }{2a}

It usually has two solutions.

But it could happen that \sqrt{b^2-4ac} then the equation doesn't have real solutions.

Or it could happen that there's only one solution, this happen when the linear equation touches the quadratic equation in one point.

And it's not possible to have more than 2 solutions. Then the answer ir 3.

For example:

In the three graphs the pink one is a quadratic function and the green one is a linear function.

In the first graph we can see that the linear function intersects the quadratic function in two points, then there are two solutions.

In the second graph we can see that the linear function intersects the quadratic function in only one point, then there is one solutions.

In the third graph we can see that the linear function doesn't intersect the quadratic function, then there aren't real solutions.

7 0
3 years ago
Find the type and number of solution for g(x) = x2 -14x = -50
inysia [295]

Answer:

Step-by-step explanation:

x² -14x+50= 0

this equation has 2 solutions because is a quadratic

the solurions are imaginary roots because the discriminant is less then 0

b²-4ac = (-14)²-4*1*50 = 194-200= -6

to find the actual roots use the quadratic formula

3 0
2 years ago
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