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tester [92]
3 years ago
7

A person can pay 18$ for a membership at a museum and then go for just 1$ per visit. What is the maximum number of visits a memb

er of the museum can make for a total cost of 50$?
Mathematics
1 answer:
Studentka2010 [4]3 years ago
6 0
<h3>Answer: 32</h3>

==================================================

Work Shown:

Let

x = number of visits

y = total cost in dollars

The membership costs $18 no matter how many visits you do. If you make x visits, at $1 each, then it costs an additional 1*x = 1x = x dollars. This is added on top of the base membership fee. In total, we know that y = 18+x = x+18

We want the total y to be at most $50. Therefore y \le 50. The highest y can get is 50.

Let's replace y with x+18 and isolate x

y \le 50

x+18 \le 50 y is replaced with x+18

x+18-18 \le 50-18 subtract 18 from both sides

x \le 32

This tells us that we can make at most 32 visits. In other words, the maximum number of visits is 32.

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3 years ago
In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A
vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

\mu_s=np=500*0.90=450

The standard deviation will be:

\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

\mu=np=300*0.932=279.6

The standard deviation will be:

\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

P(270\leq x\leq280)=P(269.5

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

P(X=280)=P(279.5

8 0
3 years ago
Which of the following is an equation of the line that passes through the point (2, 2) and is parallel to the graph of the equat
pickupchik [31]

Answer:

B

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 1 ← is in slope- intercept form

with slope m = 3

Parallel lines have equal slopes, thus

y = 3x + c ← is the partial equation of the parallel line

To find c substitute (2, 2) into the partial equation

2 = 6 + c ⇒ c = 2 - 6 = - 4

y = 3x - 4 → B

4 0
3 years ago
Read 2 more answers
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