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Natali [406]
3 years ago
5

Please tell me how to solve this, but don’t give me the answer, i want to try by myself

Mathematics
1 answer:
OLEGan [10]3 years ago
3 0

Answer:

Step-by-step explanation:

Clue 1 :

"Percent of Decrease" = ( Final Number - Initial Number ) expressed as a percentage of the Initial Number

Clue 2 :

number X expressed as a percentage of Number Y = (X/Y) x 100 %

Good luck!

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which are the roots of the quadratic function f(b) = b2 – 75? check all that apply. b = 5 square root of 3 b = -5 square root of
malfutka [58]
<span>The answers are b = 5 square root of 3; b = -5 square root of 3. f(b) = b^2 – 75. If f(b) = 0, then b^2 – 75 ) 0. b^2 = 75. b = √75. b = √(25 * 3). b = √25 * √3. b = √(5^2) * √3. Since √x is either -x or x, then √25 = √(5^2) is either -5 or 5. Therefore. b = -5√3 or b = 5√3.</span>
8 0
3 years ago
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What is the common factor of each term in the expression 2b + 5b?”
stellarik [79]
The common factor is b since they both share it.
Hope this helps
7 0
3 years ago
A conference planner has put together 280 binders for attendees and another 31 binders for presenters.how many total binders did
Ede4ka [16]

Answer:

311

Step-by-step explanation:

280 + 31 = 311

3 0
3 years ago
Find the distance between the points (-5, -10) and (2, 4).
Novay_Z [31]
Ok, so I used the equation Y2 (4) - Y1 (-10) over X2 (2) -X1 (-5).
4 - -10 is 14 since if a minus sign is before a negative number, it becomes positive.
Same goes for 2 - -5. It is 7 since the minus sign is before the negative number. Final answer is 14/7 which can be simpflied to 2/1 since 14 divided by 7 =2. So the distance is 14\7, or 2\1.
3 0
3 years ago
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If E F = 7 , A C = 16 , and A F = 9
Vilka [71]

Answers:

CB = 14

GF = 8

FB = 9

EF is parallel to CB

====================================

Explanations:

Points E and F are midpoints of their respective sides. They form the midsegment EF. Because EF is a midsegment, A midsegment is half the length of its parallel counterpart, so CB is two times longer than EF. If EF is 7 units long, then CB = 2*EF = 2*7 = 14

For similar reasons, GF is parallel to AC. If AC = 16, then half of that is GF = (1/2)*AC = 0.5*16 = 8.

FB = FA = 9 as these segments have the same single tickmark to indicate they are the same length

EF is parallel to CB because EF is a midsegment, and this is one of the properties of being a midsegment. We can show that quadrilateral EGBF is a parallelogram to help prove this.

8 0
3 years ago
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