0.1 M solution of a disaccharide solution will contain 2000 monosaccharide molecules.
<h3>What are monosaccharides?</h3>
Monosaccharides, also known as simple sugars are the simplest monomers of carbohydrates which may either be 3 carbon, 4 carbon, 5 carbon, 6 carbon or 7 carbo compounds.
There are two types of monosaccharides;
- aldoses sugars, e.g. glucose, and
- ketose sugars e.g. fructose.
When two monosaccharides are linked together by glycosidic bonds to form a single compound, the compound formed is called a disaccharide.
Considering the give question:
Suppose a 0.1M solution of a monosaccharide contains 1000 monosaccharide molecules. How many monosaccharide molecules would be in a 0.1 M solution of a disaccharide.
The number of monosaccharides molecules present in the 0.1 M solution of a disaccharide is determined as follows:
1 disaccharide molecule contains 2 monosaccharide molecules
0.1M solution of a monosaccharide contains 1000 monosaccharide molecules.
0.1 M solution of a disaccharide will contain 2 * 1000 monosaccharide molecules
0.1 M solution of a disaccharide will contain = 2000 monosaccharide molecules.
Learn more about monosaccharides and disaccharides at: brainly.com/question/731310
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Gtc atc gca this should be correct because guanain pairs with cytocine and thymine pairs with adnine
Answer:
The correct option is D) UAG, UAA, UGA
Explanation:
The amino acid sequencing code or mRNA code contains specific codes which start and stop the process of translation at the right time. If the stop codon were not present then the ribosomal machinery would have made faulty proteins. If the stop codons are not at the right place, then it results in the production of faulty proteins. The stop codons which terminate the process of translation are UAG, UAA and UGA.
The left ventricle must contract with more force in order to send blood to the body's extremities
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