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3 years ago

Tony misplaced

1 answer:

8 0

First we multiply 7 and 0.15 to see how many he lost. We get 1.50 so now we know he lost 1.50 of his collection. we add 5.55 and 1.50 and get 7.05 we divide 7.05 by 0.15 47.
Tony had 47 stamps

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Pia needs 2/3 yard of fabric to cover a bench. Which amount of fabric is greater than

Fudgin [204]

Answer:

5/6 and 7/9

Step-by-step explanation:

A and D are less than 2/3 so B and C is correct.

Hope this helps plz mark brainliest :D

6 0

3 years ago

BRAINLIEST AND 20 POINTS

Oksi-84 [34.3K]

1. Which ratios form a proportion?
a. 4/5, 20/25 -----> 4/5, 4/5 Yes
b.8/12, 18/24 -----> 2/3, 3/4 No
c. 1/3, 7/24 ------> 8/24,7/24 No
d. 2/5, 6/16 -----> 2/5, 3/8 No

2.Which ratio forms a proportion with 9/15 = 3/5
a.3/6 = 2/3 No
b.2/3 No
c.12/30 = 2/5 No
d. 6/10 = 3/5 Yes

3.Which proportion has cross products of 5 x 24 and 8x15?
a. 5/8=15/24 ----> 5 * 24 = 8 * 15 Yes
b.5/24=8/15 ----> 5 * 15 = 8 * 24 No
c.8/24=15/5 ----> 5 * 8 = 15 * 24 No
d. 15/8=5/24 ----> 15 * 24 = 5 * 8 No

3 0

3 years ago

The expression (x^22) (x^7)^3 is equivalent to x^p. What is the value of p?

SpyIntel [72]

Answer:

x^87

Step-by-step explanation:

Multiplying x^22 and x^7 results in x^29.

Then we have:

(x^29)^3 = x^87

Recall that (a^b)^c = a^(bc) and that a^b*a^c = a^(b + c)

5 0

3 years ago

In 2012 your car was worth $10,000. In 2014 your car was worth $8,850. Suppose the value of your car decreased at a constant rat

monitta

Answer:

The function to determine the value of your car (in dollars) in terms of the number of years t since 2012 is:

$f(t) = 10000(0.9407)^t$

Step-by-step explanation:

Value of the car:

Constant rate of change, so the value of the car in t years after 2012 is given by:

$f(t) = f(0)(1-r)^t$

In which f(0) is the initial value and r is the decay rate, as a decimal.

In 2012 your car was worth $10,000.

This means that $f(0) = 10000$ , thus:

$f(t) = 10000(1-r)^t$

2014 your car was worth $8,850.

2014 - 2012 = 2, so:

$f(2) = 8850$

We use this to find 1 - r.

$f(t) = 10000(1-r)^t$

$8850 = 10000(1-r)^2$

$(1-r)^2 = \frac{8850}{10000}$

$(1-r)^2 = 0.885$

$\sqrt{(1-r)^2} = \sqrt{0.885}$

$1 - r = 0.9407$

Thus

$f(t) = 10000(1-r)^t$

$f(t) = 10000(0.9407)^t$

7 0

3 years ago

Example on worksheet (subtracting by adding up)

Lisa [10]

Answer:

(49 - 29) + 1 =(50 - 29)

Step-by-step explanation:

The 20 comes from the subtraction of 29 in both sides of the previous step equality. In the following, I transcript the complete procedure and I add the step that you need to understand why 20 appears (in bold numbers):

29+20=49

49+1=50

(49 - 29) + 1 =(50 - 29)

20+1=21

50-29=21

hence, it was only nesseraty to subtract 29

3 0

3 years ago