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3 years ago

Tony misplaced

1 answer:

8 0

First we multiply 7 and 0.15 to see how many he lost. We get 1.50 so now we know he lost 1.50 of his collection. we add 5.55 and 1.50 and get 7.05 we divide 7.05 by 0.15 47.
Tony had 47 stamps

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Worksheet

Svetlanka [38]

Answer:

1a. 495 miles. 1b. 184.8 miles. 2a. 68 km. 2b. 32 kg

Step-by-step explanation:

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2 years ago

Read 2 more answers

1<br> 4<br> Joey enlarged a 3-inch by 5-inch photograph on a copy machine. He enlarged it four times. The table below<br> shows

lozanna [386]

Answer:

3) 5.4

Step-by-step explanation:

Given two points (x1, f(x1)) and (x2, f(x2)), the average rate of change is computed as follows:

[f(x2) - f(x1)]/[x2 - x1]

From the original photograph to the fourth enlargement, the points are (0, 15) and (4, 36.6). Replacing into the equation we get:

[36.6 - 15]/[4 - 0] = 5.4

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2 years ago

This is what i need help on

Scilla [17]

G2=g1*2
g3=g1*2²
196=x*4
/4 /4
49

7 0

3 years ago

A national organization has been working with utilities throughout the nation to find sites for large wind machines that generat

kap26 [50]

Answer:

B) At alpha = 0.01, there is insufficient evidence to conclude the true mean wind speed at the site exceeds 25 mph.

Step-by-step explanation:

P-value of the test:

The p-value of the test is the probability of finding a sample mean above 25.

We are using the t-distribution, with test statistic t = 1.25 and 43 - 1 = 42 degrees of freedom. This probability is a right-tailed test.

With the help of a calculator, this p-value is of 0.1091.

Since the p-value of the test is 0.1091 > 0.01, at $\alpha = 0.01$ there is insufficient evidence to conclude the true mean wind speed at the site exceeds 25 mph, and the correct answer is given by option B.

7 0

2 years ago

A person recently read that 84% of cat owners are women. How large a sample should the researcher take if she wishes to be 90% c

Lana71 [14]

Answer:

405

Step-by-step explanation:

To find sample size, use the following equation, where n = sample size, za/2 = the critical value, p = probability of success, q = probability of failure, and E = margin of error.

$n=\frac{(z_{\frac{\alpha }{2} })^{2} *p*q }{E^2}$

The values that are given are p = 0.84 and E = 0.03.

You can solve for the critical value which is equal to the z-score of (1 - confidence level)/2. Use the calculator function of invNorm to find the z-score. The value will given with a negative sign, but you can ignore that.

(1 - 0.9) = 0.1/2 = 0.05

invNorm(0.05, 0, 1) = 1.645

You can also solve for q which is 1 - p. For this problem q = 1 - 0.84 = 0.16

Plug the values into the equation and solve for n.

$n =\frac{(1.645)^2*0.84*0.16}{(0.03)^2}\\n= 404.0997333$

Round up to the next number, giving you 405.

6 0

3 years ago