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NemiM [27]
3 years ago
8

Which expressions are equivalent to -6 + 3(2+ (-4t)?

Mathematics
2 answers:
lilavasa [31]3 years ago
8 0
I can assure you that it is A
Tasya [4]3 years ago
8 0

Answer: A

Step-by-step explanation:

just do it

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Find the length of the radius of the following circle. x² + y² = 16 4 8 16
Morgarella [4.7K]
Please, when you present a list of numbers, such as 4, 8, 16, ..., separate them with commas or semicolons:  4, 8, 16, ...

If x^2 + y^2 = 16, then 16 represents r^2, and r = 4.  r cannot be negative in this type of problem.

5 0
3 years ago
Read 2 more answers
What is the additive inverse of 16 5/7 ? A.-16 7/5 B..-16 5/7 C.16 7/5 D. -16
Reil [10]

Answer:-16 5/7

Step-by-step explanation:

To find the additive inverse of 16 5/7

We get

-16 5/7

7 0
3 years ago
Work out the percentage discount offered with the family ticket option
ycow [4]

Answer:

15% discount was offered with the family ticket option.

Step-by-step explanation:

So adult is 55 so 55 x 2=110

45 x 2=90

110+90=200 so 170 ( Family ticket )

170 divide by 200=0.85 x 100=85% 100% - 85%=15%

5 0
2 years ago
A newspaper and three hot chocolates cost $7. Two newspapers and two hot chocolates cost $6. How much does one hot chocolate cos
pochemuha

Answer:

the cost of one hot chocolate is $2.

Step-by-step explanation:

Let x be the hot chocolate cost and y be the newspaper cost.

Given:

A newspaper and three hot chocolates cost $7

So, the equation is

3x+y=7--------(1)

Two newspapers and two hot chocolates cost $6

So, the second equation is.

2x+2y=6---------(2)

Find one hot chocolate cost?

Solve equation 1 for y.

3x+y=7

y=7-3x

Put y value in equation 2

2x+2(7-3x)=6

2x+14-6x=6

14-4x=6

-4x=6-14

-4x=-8

negative sign is cancelled both side.

x=\frac{8}{4}

x=2

Therefore, the cost of one hot chocolate is $2.

3 0
3 years ago
PLEASE HELP Graph 4x + y = 6x - 1 Show your work AND explain the method used to determine the graph
Anna007 [38]

Answer:

y=2x-1

Step-by-step explanation:

y= 6x-1-4x

y=2x-1

3 0
3 years ago
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