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mash [69]
3 years ago
6

Nick thought of a counting number, and then he added the next counting number to it. He got the sum of 79. What was Nick's numbe

r?
Mathematics
1 answer:
77julia77 [94]3 years ago
4 0
X + x+1 = 79
2x + 1 - 1 = 79 - 1
2x = 78
2x/2 = 78/2
x=39
Nick's number was 39
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Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x
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ANSWER

1.39

EXPLANATION

The given quadratic equation is

0 = 2 {x}^{2}  + 3x - 8

This is the same as,

2 {x}^{2}  + 3x - 8 = 0

Comparing to

a {x}^{2}  + bx  + c = 0

We have

a=2, b=3,c=-8

Using the quadratic formula, the solution is given by:

x =  \frac{ - b \pm \:  \sqrt{ {b}^{2}  - 4ac} }{2a}

We substitute the values to get,

x =  \frac{ - 3\pm \:  \sqrt{ {3}^{2}  - 4(2)( - 8)} }{2(2)}

x =  \frac{ - 3\pm \:  \sqrt{ 73} }{4}

The positive root is

x =  \frac{ - 3 + \:  \sqrt{ 73} }{4} = 1.39

to the nearest hundredth.

4 0
3 years ago
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WHAT AM I DOING WRONG?
hram777 [196]

Answer:

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Step-by-step explanation:

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Graph y=2x+4 how do i solve this i really need help
chubhunter [2.5K]
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3 0
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Y=5x+17 and y=5x -2 are two parallel lines. Explain why.
tigry1 [53]
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Vladimir79 [104]

Answer:

Yes, it can be generated if p = \frac{n}{n+1}, where n is a positive even integer.

Step-by-step explanation:

An odds for an event, is the probability or chance that this event will occur, divided by the probability that it will not occur.

Assume that the probability of getting tail when throwing the coin is p, therefore, the probability of getting a head is (1-p) and the odds for the event of getting tail is \frac{p}{1-p}.

If k is a positive integer, and we assume that the odds of getting a tail are even, then:

\frac{p}{1-p} = 2k

p = 2k - 2kp

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Conclusion: if p = \frac{2k}{2k+1}, for some positive integer k, even odds are generated. For example: p = 2/3, 4/5, 6/7, ...

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