Answer:
4x^2 +9xy +6y^2
Step-by-step explanation:
Combine like terms. I find it useful to factor out the variable part of the expression so I can see what coefficients are being combined.
7x^2+5xy-3y^2 - (2x^2+3xy-5y^2 + x^2-7xy-4y^2)
= (7 -2 -1)x^2 +(5 -3+7)xy +(-3 +5 +4)y^2
= 4x^2 +9xy +6y^2
The multiples of 14 are 1,2,7,14
the multiples of 22 are 1,2,11,22
Therefore 2 is the GCF
<span>L the length W the width
The length of a rectangle is 5 more than twice the width</span>
L = 5+ 2W
<span>the perimeter is equal the sum of sides =130
</span>
L+L+W+W =130
by subtitution we replace L by <span>L = 5+ 2W
</span>5+ 2W+<span>5+ 2W +W+W = 130
</span>
6W= 120
w= 20 <span>L = 5+ 2W= 5+ 40=45</span>
Answer:
A landform is a feature on the Earth's surface that is part of the terrain. Mountains, hills, plateaus, and plains are the four major types of landforms. Minor landforms include buttes, canyons, valleys, and basins. Tectonic plate movement under the Earth can create landforms by pushing up mountains and hills.
The length of a segment is the distance between its endpoints.

- AB and CD are not congruent
- AB does not bisect CD
- CD does not bisect AB
<u>(a) Length of AB</u>
We have:


The length of AB is calculated using the following distance formula

So, we have:


Simplify

<u>(b) Are AB and CD congruent</u>
First, we calculate the length of CD using:

Where:


So, we have:



By comparison

Hence, AB and CD are not congruent
<u>(c) AB bisects CD or not?</u>
If AB bisects CD, then:

The above equation is not true, because:

Hence, AB does not bisect CD
<u>(d) CD bisects AB or not?</u>
If CD bisects AB, then:

The above equation is not true, because:

Hence, CD does not bisect AB
Read more about lengths and bisections at:
brainly.com/question/20837270