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3 years ago

What is the fifth term in the sequence defined by f(n)=3(n-3)

Mathematics

1 answer:

stich3 [128]3 years ago

7 0

It is 6
I got that by adding 5 into n's place
F(n)=3(5-3)
3x5= 15 3x3=9
15-9=6
I really hope this helps!! :)

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(84x - 69y) - (65x + 34y)

Svetach [21]

(84x - 69y) - (65x + 34y)

Remove the parenthesis and combine the like terms:

84x - 65x = 19x

-69y - 34y = -103y

Combine for final answer:

19x -103y

6 0

3 years ago

What is the following product

frosja888 [35]

I would pick C sorry if it’s wrong

3 0

3 years ago

Read 2 more answers

A sample size 25 is picked up at random from a population which is normally

Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that $\mu = 100, \sigma = \sqrt{36} = 6$

Sample of 25:

This means that $n = 25, s = \frac{6}{\sqrt{25}} = 1.2$

(a) P(X<99)

This is the pvalue of Z when X = 99. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{99 - 100}{1.2}$

$Z = -0.83$

$Z = -0.83$ has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

$Z = \frac{X - \mu}{s}$

$Z = \frac{100 - 100}{1.2}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5

X = 98

$Z = \frac{X - \mu}{s}$

$Z = \frac{98 - 100}{1.2}$

$Z = -1.67$

$Z = -1.67$ has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

P(98 < X < 100) = 0.4525

6 0

3 years ago

1. A box contains 10 blue Stickers, 15 red stickers , and 25 orange stickers . A sticker is selected and its color noted. Then i

denis-greek [22]

Answer:

1/25 ; 3/20 ; 3/50

Step-by-step explanation:

Total number of stickers :

(10 + 15 + 25) = 50 stickers

Probability = required outcome / Total possible outcomes

a. Selecting blue and blue stickers

P(First blue) = 10/50 = 1/5

P(second blue) = 10/50 = 1/5

1/5 * 1/5 = 1 / 25

b. Selecting one red sticker and then one orange sticker

P(First red) = 15/50 = 3/10

P(second orange) = 25/50 = 1/2

3/10 * 1/2 = 3 /20

Selecting one red sticker and then one blue sticker

P(First red) = 15/50 = 3/10

P(second blue) = 10/50 = 1/5

3/10 * 1/5 = 3 / 50

4 0

3 years ago

I need answers 1-4 please!

madreJ [45]

1. Horizontal asymptotes: None
Vertical asymptote: x=-2
RD: 2
Domain: First picture
Range: first pic

2.HA: y=1
VA: x= -5 negative
RD: x= 5 no negative
Domain: second pic
Range second pic

3.HA: y=0
VA: x=-4,4
RD: none
D: 3rd pic
R: 3rd pic

4.HA: none
VA: x=3
RD: x=-2
D: 4th
R: 4th

I hope this helps!!!!!!!

8 0

3 years ago