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3 years ago

The population of cats that are rescued every year is currently 50,000 and declines at a rate of 1.2% every year. This models

Mathematics

1 answer:

larisa86 [58]3 years ago

8 0

This models exponential decay.

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In a 2-card hand, what is the probability of holding only face cards?

SVEN [57.7K]

Answer:

Step-by-step explanation:

( J , Q, K 4 each)

so prob that for 2 cards, both cards are face

= C(12,2)/C(52,2) = 66/1326 = 11/221

4 0

3 years ago

Coordinate plane with triangle EFG with E at 0 comma 5, F at 1 comma 1, and G at negative 2 comma 1. Point H at 1 comma 1 is on

Oksana_A [137]

Answer:

Triangle EFG is dilated by a scale factor of 2 centered at (0, 2) to create triangle E'F'G'. Which statement is true about the dilation?

segment EG ≅ segment E prime G prime.

The slope of segment EF is the same as the slope of segment E prime H prime.

segment H prime F prime will overlap segment HF.

segment EH and segment E prime H prime both pass through the center of dilation.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

How do we solve this??

jasenka [17]

Answer:

Y= 42

Step-by-step explanation:

The answer would be 42 because if x=9 and the equation is 5x you have to multiply and that will give you 45 and then subtract 3 which would give you 42

4 0

3 years ago

Read 2 more answers

15. What is the width of each bin? (1 point)

Pavel [41]

15) Answer is B because you can clearly see it's only 1 inch

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3 years ago

An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est

MrRa [10]

Answer:

85% level of the confidence interval is

(26.337, 26.662)

Step-by-step explanation:

Explanation:-

Given the size of the sample 'n' = 295

Mean of the sample x⁻ = 26.5

The Standard deviation of the Population = 2.7

85% level of the confidence interval is determined by

$(x^{-} - Z_{0.15} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.15} \frac{S.D}{\sqrt{n} })$

Critical value Z₀.₁₅ = 1.036

85% level of the confidence interval is determined by

$(x^{-} - Z_{0.15} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.15} \frac{S.D}{\sqrt{n} })$

$(26.9 -1.036 \frac{2.7}{\sqrt{295} } , 26.5 + 1.036 \frac{2.7}{\sqrt{295} })$

( 26.5 - 0.1628 , 26.5+0.1628)

(26.3372,26.6628)

7 0

3 years ago