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Anuta_ua [19.1K]

3 years ago

8

A triangular brace has an angle measure of 92 degrees, with a side opposite this angle measuring 10 inches. The base of the tria

ngular brace, which is adjacent to the given angle measure, is 12 inches in length. Which of the following statements is correct?
A. There is not a solution for the angle opposite the side measuring 12 inches.
B. The angle opposite the side measuring 12 inches has two solutions of approximately 24 degrees and 36 degrees
C. The angle opposite the side measuring 12 inches has one solution of approximately 24 degrees.
D. The angle opposite the side measuring 12 inches has one solution of approximately 32 degrees.

2 answers:

vova2212 [387]3 years ago

7 0

I think the answer is D

Stells [14]3 years ago

3 0

I think to that D is answer

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Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2). What is the area of the triangle? a 18 square units b 9 square unit

natka813 [3]

Answer:

Option C. 6 square units

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

Let

a,b,c be the lengths of the sides of a triangle.

The area is given by:

$A=\sqrt{p(p-a)(p-b)(p-c)}$

where

p is half the perimeter

p= $\frac{a+b+c}{2}$

we have

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$d=\sqrt{(-3-1)^{2}+(-2+2)^{2}}$

$d=\sqrt{(-4)^{2}+(0)^{2}}$

$dAB=4\ units$

step 2

Find the distance BC

$d=\sqrt{(-2+3)^{2}+(1+2)^{2}}$

$d=\sqrt{(1)^{2}+(3)^{2}}$

$dBC=\sqrt{10}\ units$

step 3

Find the distance AC

$d=\sqrt{(-2-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-3)^{2}+(3)^{2}}$

$dBC=\sqrt{18}\ units$

step 4

$a=AB=4\ units$

$b=BC=\sqrt{10}\ units$

$c=AC=\sqrt{18}\ units$

Find the half perimeter p

p= $\frac{4+\sqrt{10}+\sqrt{18}}{2}=5.70\ units$

Find the area

$A=\sqrt{5.7(5.7-4)(5.7-3.16)(5.7-4.24)}$

$A=\sqrt{5.7(1.7)(2.54)(1.46)}$

$A=\sqrt{35.93}$

$A=6\ units^{2}$

7 0

3 years ago

If AC is parallel to DE, find X

UNO [17]

Answer: x = 50

Concept:

Here, we need to know the idea of alternative interior angles and the angle sum theorem.

<u>Alternative interior angles</u> are angles that are formed inside the two parallel lines, and the values are equal.

The <u>angle sum theorem</u> implies that the sum of interior angles of a triangle is 180°

If you are still confused, please refer to the attachment below or let me know.

Step-by-step explanation:

<u>Given information:</u>

AC ║ DE

∠ABC = 85°

∠A = 135°

<u>Find the value of ∠BAC</u>

∠A + ∠BAC = 180° (Supplementary angle)

(135°) + ∠BAC = 180°

∠BAC = 45°

<u>Find the value of ∠BCA</u>

∠ABC + ∠BAC + ∠BCA = 180° (Angle sum theorem)

(85°) + (45°) + ∠BCA = 180°

∠BCA = 50°

<u>Find the value of x (∠EBC)</u>

∠EBC ≅ ∠BCA (Alternative interior angles)

Since, ∠BCA = 50°

Therefore, ∠EBC = 50°

$\Large\boxed{x=50}$

Hope this helps!! :)

Please let me know if you have any questions

8 0

1 year ago

write a linear equation that intersects y=x^2 at two points. Then write a second linear equation that intersects y=x^2 at just o

Liula [17]

We know that $y = x^2$ is a parabola, concave up, with vertex in the origin $(0,0)$

So, we may use three horizontal lines for our purpose: any horizontal line above the x axis will intersect the parabola twice. The x axis itself intersects the parabola once on the vertex, while any horizontal line below the x axis won't intercept the parabola.

Here's the examples:

The horizontal line $y = 4$ intercepts the parabola twice: the system $y = x^2,\ y = 4$ is solved by $x^2=4 \implies x = \pm 2$
The horizontal line $y=0$ intercepts the parabola only once: the system is $y=x^2,\ y=0$ which yields $x^2=0\implies x=0$ which is a repeated solution
The horizontal line $y=-5$ intercepts the parabola only once: the system is $y=x^2,\ y=-5$ which yields $x^2=-5$ which is impossible, because a squared number can't be negative.

5 0

3 years ago

While riding her bike to the ocean and back home 55 times, kimberly timed herself at 48min48⁢min, 48min48⁢min, 49min49⁢min, 46mi

Vsevolod [243]

Total of 5 times = 48 + 48 + 49 + 46 + 64 = 255 mins

Goal:
Average = 53 mins
Total = 53 x 6 = 318 mins

6th ride = 318 - 255 = 63 mins

Answer: She needs to attain 63 mins for her 6th ride.

3 0

3 years ago

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irga5000 [103]

It would be 7.54 because you fist have to put the numbers ordered smallest to biggest amount 7.15, 7.44, 7.48,7.60, 7.72, 7.73 so the numbers that are in the middle are 7.48 and 7.60 you add them up, and the result you divide by 2 which gives you 7.54.

3 0

3 years ago