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rusak2 [61]
3 years ago
6

Determine whether the statement below is true or false. A function is increasing on an open interval I if, for any choice of x1

and x2 in I, with x1 < x2 we have f(x1) > f(x2).
Mathematics
1 answer:
ELEN [110]3 years ago
7 0

Answer: False.

Step-by-step explanation:

This says;

If we have an interval I, f(x) is increasing if, for any two x1, x2 such that:

x1 ∈ I and x2 ∈ I.

where x2 > x1, ----> f(x1) > f(x2).

An increasing function means that, if the value of x increases, also does the value of f(x).

Particularly, here we have that x2 > x1

so x can increase from x1 to x2.

But we have that f(x1) > f(x2)

So here we can see that the actual value of f(x) decreases as x increases.

Then this is not a increasing function, so the statement is false.

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Answer: B

Step-by-step explanation:

If an absolute value of a negative number plus a absolute value of the positive number is positive. Absolute value of anything is positive.

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3 years ago
What point the equation
Maslowich

Answer:

The Answer to the question is C

Step-by-step explanation:


3 0
3 years ago
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The authors of a paper describe an experiment to evaluate the effect of using a cell phone on reaction time. Subjects were asked
Serggg [28]

Answer:

a) The 99% confidence interval would be given by (24.409;24.979)  

b) n=464

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=47-1=46  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,46)".And we see that t_{\alpha/2}=2.01  

Now we have everything in order to replace into formula (1):  

525-2.01\frac{75}{\sqrt{47}}=503.01  

525+2.01\frac{75}{\sqrt{47}}=546.99  

So on this case the 95% confidence interval would be given by (503.01;546.99)

Part b

The margin of error is given by this formula:  

ME=t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

And on this case we have that ME =7 msec, we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{t_{\alpha/2} s}{ME})^2 (2)  

The critical value for 95% of confidence interval is provided, t_{\alpha/2}=2.01 from part a, replacing into formula (2) we got:  

n=(\frac{2.01(75)}{7})^2 =463.79 \approx 464  

So the answer for this case would be n=464 rounded up to the nearest integer  

8 0
3 years ago
What is the y-intercept of the line shown?
lys-0071 [83]
Simple.....

always remember the y-intercept is where your line hits the y-axis... or where it hits the vertical axis...

As we can see this line hits the y-axis at (0,3)-->> y-intercept=3

Thus, your answer.
6 0
3 years ago
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Find the least common multiple of 18, 24 *
emmainna [20.7K]

Answer:

72

Step-by-step explanation:

Find the prime factorization of 18

18 = 2 × 3 × 3

Find the prime factorization of 24

24 = 2 × 2 × 2 × 3

Multiply each factor the greater number of times it occurs in steps above to find the LCM:

LCM = 2 × 2 × 2 × 3 × 3

LCM = 72

i hope this helps :)

7 0
3 years ago
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