The two sides are equal and for that reason DE = CE as shown below :
AD = BC, DF = GC
E = A(F) and E = BG, therefore A(F) = BF
<h3>Description of rectangle</h3>
Now we all know that a rectangle has four edges which are A, B, C, D.
when we divide the bottom line, which is the line from point C to D into three parts we will have ( DF, FG, and GC )
From the question we know that DF = GC
E is the intersection of A(F) and BG
we can now Prove that DE = CE.
since D and C are point included in E and since this is a rectangle
AD = BC, DF = GC
E = A(F) and E = BG, therefore A(F) = BF
DE = CE
We can conclude by saying that in a rectangle two sides are equal and for that reason DE = CE
Learn more about Rectangle : brainly.com/question/22148953
Answer:
<h3>27</h3>
Step-by-step explanation:
Given
f(x)= x^2-2 and g(x) = 4f (x)-1
g(x) = 4(x^2-2) - 1
g(x) = 4x²-8-1
g(x) = 4x²-9
Get g(-3):
g(-3) = 4(-3)²-9
g(-3 = 4(9) - 9
g(-3) = 36-9
g(-3) = 27
Answer:
r
Step-by-step explanation:
sin is o/h so across from 12 would be the angle r
Answer:
infinite
Step-by-step explanation:
