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3 years ago

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Pls I really need help

1 answer:

Masteriza [31]3 years ago

3 0

Answer:

6.x8/929298+9082'1

Step-by-step explanation:

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The four points (−2, 5), (−2, −1), (6, −1), and (3, 5) are the vertices of a polygon. What is the area, in square units, of this

crimeas [40]

Look at the picture.

The polygon is a right-angled trapezoid.

The area is:
$A=\frac{a+b}{2} \times h$

The points (-2,-1) and (6,-1) lie on the same horizontal line, so the distance between them is 6-(-2)=6+2=8. The length of a is 8 units.
The points (-2,5) and (3,5) lie on the same horizontal line, so the distance between them is 3-(-2)=3+2=5. The length of b is 5 units.
The points (-2,5) and (-2,-1) lie on the same vertical line, so the distance between them is 5-(-1)=5+1=6. The length of h is 6 units.

$A=\frac{8+5}{2} \times 6=\frac{13}{2} \times 6=13 \times 3=39$

The area is 39 square units.

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3 years ago

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Name at least one advantage of credit cards.

vaieri [72.5K]

You are able to pay expensive dues forward, such as houses, cars, and other payments that you wouldn't be able to pay in full on the spot.

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3 years ago

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Can someone please help me .

dusya [7]

Answer:

for 10. a

for 11. f.

Step-by-step explanation:

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3 years ago

Factor completely 3x2 + 6x - 7x - 14

Mice21 [21]

Answer:(3x+7)(x+2)

Step-by-step explanation:

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3 years ago

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Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat

yulyashka [42]

Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

$P(t) = 0.8t^{2} + 6t + 19000$

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

$P(t) = 0.8t^{2} + 6t + 19000$

$0.8t^{2} + 6t + 19000 = 34200$

$0.8t^{2} + 6t - 15200 = 0$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$0.8t^{2} + 6t - 15200 = 0$

So $a = 0.8, b = 6, c = -15200$

Then

$\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356$

$t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14$

$t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64$

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

6 0

3 years ago