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ikadub [295]
4 years ago
11

A 55W light bulb will allow 0.5A to flow through it. If the outlet provides a potential difference of 110V, how much resistance

is provided by the bulb?
Physics
2 answers:
Vinil7 [7]4 years ago
7 0

Explanation:

110=0.5×R

R=220 ohms

resistance of the light bulb=220 ohms

Yuri [45]4 years ago
3 0

Answer: resistance = 220 ohms

Explanation: given that

Power P = 55W

Current I = 0.5A

Potential difference V = 110V,

Using the formula

P = IV =V^2/R

55 = 110^2/R

R = 12100/ 55

R = 220 ohms

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Answer:

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Explanation:

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Vadim26 [7]

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3 years ago
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Answer:

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Answer:

D

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