Answer:
41.02m
Explanation:
Given parameters:
Initial velocity = 0m/s
Final velocity = 96km/hr
Time taken = 3.07s
Unknown:
Distance traveled by the time the final speed was achieved = ?
Solution:
To solve this problem, we first find the acceleration of the car;
Acceleration = 
v is the final velocity
u is the initial velocity
t is the time taken
Now convert the the final velocity to m/s;
96km/hr to m/s;
1 km/hr = 0.278m/s
96km/hr = 96 x 0.278 = 26.7m/s
Now;
Acceleration = 
= 8.69m/s²
So;
v² = u² + 2as
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance
26.7² = 0² + 2 x 8.69 x s
712.89 = 17.38s
s = 41.02m
Answer:
second month = 0.5² = 1/4 of original
third month = 0.5³ = 1/8 of original
Explanation:
Answer:
65.14 Hz
Explanation:
We have given the capacitance 
And the capacitive reluctance = 268 ohm
The capacitive reluctance of a capacitive circuit is given by
Answer:.
F = 3.0576sinθ
For any value of θ < 180
Explanation:
Generally, F = BILsinθ
Where,. F = magnetic force magnitude. B = magnetic Field magnitude.
L = length of wire. I = current
Therefore,
B = 0.260 T, L = 2.80 m
I = 4.20 A
: F = 0.260 × 4.20 × 2.80sinθ
∴ F = 3.0576sinθ
The period of a simple pendulum depends only on the length of the pendulum and the gravitational acceleration:
where L is the pendulum length and g the gravitational acceleration.
The problem says that Maya and the swing form a simple pendulum, so we can use this formula to calculate the period of Maya's motion, using the length of the swing (L=1.8 m):
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