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2 years ago

What units is the Metric System of Measurement based on?

Physics

1 answer:

Alex787 [66]2 years ago

3 0

Answer:

metre for length and the kilogram for Mass

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How can humans increase the rate of endangered of extinct species

labwork [276]

I would think A. Reduce Environmental Impacts.

If you build and populate more zoos, some of the endangered species might not be able to survive in captivity

If you introduce new predators they are going to kill all the endangered species and if you pass new laws about land use some people may kill the species

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How can I feel pain when I hit a table with my bare hands (Physics)

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When your hand hits the table the table will vibrate and your hand will be numb for two to three seconds

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3 years ago

Conductors of electricity * A.Nonmetal B-Metalloid C-Metal

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Answer:

Conductors of electricity?

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2 years ago

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7. A 1.0 kg metal head of a geology hammer strikes a solid rock with a velocity of 5.0 m/s. Assuming all the energy is retained

marta [7]

The increase in temperature of the metal hammer is 0.028 ⁰C.

The given parameters:

mass of the metal hammer, m = 1.0 kg
speed of the hammer, v = 5.0 m/s
specific heat capacity of iron, 450 J/kg⁰C

The increase in temperature of the metal hammer is calculated as follows;

$Q = K.E\\\\mc \Delta T = \frac{1}{2} mv^2\\\\\Delta T = \frac{v^2}{2 c}$

where;

c is the specific heat capacity of the metal hammer

Assuming the metal hammer is iron, c = 450 J/kg⁰C

$\Delta T = \frac{5^2}{2 \times 450} \\\\\Delta T = 0.028 \ ^0C$

Thus, the increase in temperature of the metal hammer is 0.028 ⁰C.

Learn more about heat capacity here: brainly.com/question/16559442

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2 years ago

The current in a circuit is tripled by connecting a 580 resistor in parallel with the resistance of the circuit. Determine the r

const2013 [10]

Answer:

1160 ohm

Explanation:

We are given that

R'=580 ohm

Current=3 I

We have to find the resistance of the circuit.

Let R be the resistance of circuit.

In parallel

$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}$

Using the formula

$\frac{1}{R_{eq}}=\frac{1}{580}+\frac{1}{R}=\frac{580+R}{580R}$

$R_{eq}=\frac{580R}{580+R}$

In parallel combination,Potential difference across each resistance remains same.

$V=IR$

Using the formula

$IR=3IR_{eq}$

$IR=3I\times \frac{580R}{580+R}$

$580+R=3\times 580=1740$

$R=1740-580=1160\Omega$

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2 years ago