Answer:
(a) =34.0J
(b) = 13.038m/s
(c) =
Explanation:
(a) mass (m) =0.45kg
Height(h) =8.5m
Gravity (g) =10m/s^2
But P. E (Potential Energy) = mass × gravity × height
P. E = 0.45×10×8.5
P. E = 34.0J
(b) using v^2=u^2 - 2gs
Where v = final velocity
u= initial velocity
g = gravity
s =distance
But at maximum height <u>v</u><u> </u>=0
0^2= u^2 - 2gs
Transpose u^2 we have
u^2 = 2gs
u^2 = 2×10×8.5
u^2 = 170
u = square root of 170
u = 13.038m/s
Answer:
A) V=198.75m/s
B) 793.7mts
C) Vx=158.72m/s
D) Vy=-168.71m/s
Explanation:
In order to answer the first question we need to calculate the initial speed of the projectile because it's the same speed of the plane.

The velocity has to be negative because is going down so, Voy=-119.61m/s
now that we have the Y component of velocity we can get the plane velocity by:
the angle with the horizontal is ∝=-90+53=-37

Now that we have the Initial velocity we can calculate the horizontal displacement:

Because the horizontal velocity remains the same, it is given by:

In order the calculate the Y componet we will use the next formula:

Answer:
option C
Explanation:
given,
Temperature of the surface = 6000 K
using formula to calculate 

is the maximum wavelength emission in meter.
T is the temperature in kelvin.




the wavelength is in Visible range
The Correct answer is option C
Density = mass / volume
So..
1.06 = mass / 473.176
Multiply 473.176 over to the other side leading to
(1.06)(473.176) = mass
mass = 501.56656 --> 501.57
Answer:
To find the slope, we need to have co-ordinates of atleast 2 points lying on the line.
In this case, the 2 points are
(-3,1) and (2,-2)
To find the gradient we put in the following rule :
Rise / Run = (y2 - y1) / (x2-x1) = (-2-1) / (2+3) = -3 /5
Explanation: