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3 years ago

A material that can easily flow is called a

Physics

2 answers:

Blababa [14]3 years ago

6 0

Answer:

a. fluid

Explanation:

A fluid is any body that has the property to flow, and lacks rigidity and elasticity, and consequently yields immediately to any force tending to alter its shape and thus adopting the shape of its container. Fluids can be liquids or gases according to the different intensity of the cohesion forces existing between their molecules. In liquids, intermolecular forces allow particles to move freely, although they maintain latent bonds that cause substances in this state to have a constant or fixed volume. Gases, by contrast, consist of well-separated moving particles that collide with each other and try to disperse, such that the gases have no defined shape or volume.

murzikaleks [220]3 years ago

3 0

A material that can easily flow is called a...

A. Fluid.

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Which SI unit is the correctly abbreviated for describing the mass on an object.

djverab [1.8K]

S.I. Unit of mass is Kilogram which is denoted by Kg

In short, Your Answer would be Option C

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3 years ago

How would you explain conduction?

alexira [117]

Answer:

the meaning of conduction is the process by which heat or electricity is directly transmitted through a substance when there is a difference of temperature or of electrical potential between adjoining regions, without movement of the material.

Explanation:

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2 years ago

Read 2 more answers

The 1.53-kg uniform slender bar rotates freely about a horizontal axis through O. The system is released from rest when it is in

OlgaM077 [116]

Answer:

The spring constant = 104.82 N/m

The angular velocity of the bar when θ = 32° is 1.70 rad/s

Explanation:

From the diagram attached below; we use the conservation of energy to determine the spring constant by using to formula:

$T_1+V_1=T_2+V_2$

$0+0 = \frac{1}{2} k \delta^2 - \frac{mg (a+b) sin \ \theta }{2} \\ \\ k \delta^2 = mg (a+b) sin \ \theta \\ \\ k = \frac{mg(a+b) sin \ \theta }{\delta^2}$

Also;

$\delta = \sqrt{h^2 +a^2 +2ah sin \ \theta} - \sqrt{h^2 +a^2}$

Thus;

$k = \frac{mg(a+b) sin \ \theta }{( \sqrt{h^2 +a^2 +2ah sin \ \theta} - \sqrt{h^2 +a^2})^2}$

where;

$\delta$ = deflection in the spring

k = spring constant

b = remaining length in the rod

m = mass of the slender bar

g = acceleration due to gravity

$k = \frac{(1.53*9.8)(0.6+0.2) sin \ 64 }{( \sqrt{0.6^2 +0.6^2 +2*0.6*0.6 sin \ 64} - \sqrt{0.6^2 +0.6^2})^2}$

$k = 104.82\ \ N/m$

Thus; the spring constant = 104.82 N/m

The angular velocity can be calculated by also using the conservation of energy;

$T_1+V_1 = T_3 +V_3 \\ \\ 0+0 = \frac{1}{2}I_o \omega_3^2+\frac{1}{2}k \delta^2 - \frac{mg(a+b)sin \theta }{2} \\ \\ \frac{1}{2} \frac{m(a+b)^2}{3} \omega_3^2 + \frac{1}{2} k \delta^2 - \frac{mg(a+b)sin \ \theta }{2} =0$